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Leto [7]
2 years ago
7

If a car is moving 7.0m/s and has 62J of energy, how much mass does it have ?

Physics
1 answer:
Ede4ka [16]2 years ago
7 0

Answi am sorry but i do not know the answer

Explanation:

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Please explain what is a Energy is
professor190 [17]

Answer:

<h2><u>The capacity or power to do work/ The ability to do work. </u></h2>

Explanation:

such as the capacity to move an object (of a given mass) by the application of force. Energy can exist in a variety of forms, such as electrical, mechanical, chemical, thermal, or nuclear, and can be transformed from one form to another

I hope this help:)

8 0
2 years ago
A person does work equal to 2500 J in climbing a tree of height 5 m. What is the mass of the person? The value of g = 9.8 ms². (
seraphim [82]

Answer:

51kg

Explanation:

w=FxS

2500=Fx5

F=2500/5=500

mass = 500/9.8 = 51kg

7 0
2 years ago
What is produced as the result of unequal warming of the earth's surface?
Soloha48 [4]
Unusual precipitation patterns 
7 0
3 years ago
Because the Triple Beam Balance is zeroed before being put into use, it measures
pickupchik [31]

Answer:

B

Explanation:

8 0
3 years ago
A 4.00 m long, massless beam rests horizontally on a support 3.00 m from the left
Rus_ich [418]

If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Given the data in the question;

  • Length of the massless beam;L = 4.00m
  • Distance of support from the left end; x = 3.00m
  • First mass; m1 = 31.3 kg
  • Distance of beam from  the left end( m₁ is attached to ); x_1 = ?
  • Second mass; m_2 = 61.7 kg
  • Distance of beam from  the right of the support( m₂ is attached to ); x_1 = 0.273m

Now, since it is mentioned that the beam is in static equilibrium, the Net Torque on it about the support must be zero.

Hence, m_1g( x-x_1) = m_2gx_2

we divide both sides by g

m_1( x-x_1) = m_2x_2

Next, we make x_1, the subject of the formula

x_1 = x - [ \frac{m_2x_2}{m_1} ]

We substitute in our given values

x_1 = 3.00m - [ \frac{61.7kg\ * \ 0.273m}{31.3kg} ]

x_1 = 3.00m - 0.538m

x_1 = 2.46m

Therefore, If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Learn more; brainly.com/question/3882839

6 0
3 years ago
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