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olga_2 [115]
3 years ago
13

A car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of 1.85 m/s2

. The car makes it one quarter of the way around the circle before it skids off the track. From these data, determine the coefficient of static friction between the car and track.
Physics
1 answer:
Tasya [4]3 years ago
7 0

Answer:

Coefficient of friction = 0.836

Explanation:

If v be the speed after one quarter of the circular path

v² = 2as = 2 x 1.85 x 2πr/4 ; v²/r = 1.85 x 3.14 = 5.8

tangential acceleration = 5.8 m/s²

radial acceleration = v² /r = 5.8

total acceleration = √2 x 5.8

m x√2 x 5.8 = m x g xμ

μ = √2 x 5.8 / 9.8 = 0.836

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help me please ASAP ​
vagabundo [1.1K]

Answer:

F = 1200 [N]

Explanation:

Torque is defined as the product of force by Radius.

T=F*r

where:

T = torque = 300 [N*m]

r = radius = 50/2 = 25 [cm] = 0.25 [m]

F=T/r\\F = 300/0.25\\F = 1200 [N]

3 0
3 years ago
In order for an object to sink, its density must ___________ 1g/ml.
Tju [1.3M]
In order for an object to sink, its density must be greater than 1g/ml. 
7 0
3 years ago
Read 2 more answers
The plate area is doubled, and the plate separation is reduced to half its initial separation. What is the new charge on the neg
Norma-Jean [14]

Answer:

 Q = 4 Q₀

Explanation:

This is an exercise on capacitors, where the capacitance is

         C =  \epsilon_{o} \    \frac{A}{d}

if we apply the given conditions

         C = \epsilon_{o} \    \frac{2A}{0.5d}

         C = 4 \epsilon_{o} \    \frac{A}{d}

let's call the capacitance Co with the initial values

         C₀ = \epsilon_{o} \    \frac{A}{d}

         C = 4 C₀

The charge on each plate of a capacitor is

           Q = C ΔV

If the potential difference is maintained, the new charge is

       Q = 4 C₀ ΔV

       

let's call

        Q₀ = C₀ ΔV

we substitute

        Q = 4 Q₀

5 0
2 years ago
Five lamp, each labbled "6V,3W" are operated at normal brightness. What is the total energy supplied to the lamps in five second
REY [17]

Answer:

E = 75 J

Explanation:

First, we will calculate the total power consumed by the five lamps:

Total\ Power = P = (5)(Power\ of\ one\ lamp)\\P = (5)(3\ W)\\P = 15\ W

Now, the energy supply can be calculated as follows:

E = Pt

where,

E = Energy = ?

t = time = 5 s

Therefore,

E = (15 W)(5 s)

<u>E = 75 J</u>

8 0
2 years ago
(A) Electricity and Magnetism
Maksim231197 [3]

electricity

Explanation:

the position (2,o

5 0
3 years ago
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