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4 years ago

12

8. Semiconductors

1 answer:

Andreas93 [3]4 years ago

5 0

do not obey ohm's law so it's a I believe

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(8c7p26) During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with lar

likoan [24]

Answer: 1175 J

Explanation:

Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."

Given

Spring constant, k = 102 N/m

Extension of the hose, x = 4.8 m

from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m

Work done =

W = 1/2 k [x(i)² - x(f)²]

Since x(f) = 0, then

W = 1/2 k x(i)²

W = 1/2 * 102 * 4.8²

W = 1/2 * 102 * 23.04

W = 1/2 * 2350.08

W = 1175.04

W = 1175 J

Therefore, the hose does a work of exactly 1175 J on the balloon

7 0

3 years ago

If velocity is positive, which woul

shusha [124]

Answer:

C. An inital volocity that is faster than the final volocity

Explanation:

.

5 0

3 years ago

A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio

Blababa [14]

Answer:

(B) 1.6 m/s^2

Explanation:

The equation of the forces acting on the box in the direction parallel to the slope is:

$mg sin \theta - \mu N = ma$ (1)

where

$mg sin \theta$ is the component of the weight parallel to the slope, with m = 6.0 kg being the mass of the box, g = 9.8 m/s^2 being the acceleration of gravity, $\theta=39^{\circ}$ being the angle of the incline

$\mu N$ is the frictional force, with $\mu = 0.6$ being the coefficient of kinetic friction, N being the normal reaction of the plane

a is the acceleration

The equation of the force along the direction perpendicular to the slope is

$N-mg cos \theta =0$

where $mg cos \theta$ is the component of the weight in the direction perpendicular to the slope. Solving for N,

$N=mg cos \theta$

Substituting into (1), solving for a, we find the acceleration:

$a=gsin \theta- \mu g cos \theta=(9.8)(sin 39^{\circ})-(0.6)(9.8)(cos 39^{\circ})=1.6 m/s^2$

6 0

4 years ago

School homework about multiplying fractions <br><br>worth 30 brainly points

RoseWind [281]

Answer:

Explanation:

1. $\frac{1}{3}$ x $\frac{6}{7}$ = $\frac{6}{21}$

= $\frac{2}{7}$

b. $\frac{6}{8}$ + $\frac{4}{9}$ = $\frac{24}{72}$

= $\frac{1}{3}$

c. $\frac{10}{15}$ x $\frac{3}{4}$ = $\frac{30}{60}$

= $\frac{1}{2}$

d. $\frac{7}{10}$ of $\frac{5}{10}$ = $\frac{7}{10}$ x $\frac{5}{10}$

= $\frac{35}{100}$

= $\frac{7}{20}$

e. $\frac{3}{8}$ of $\frac{4}{6}$ = $\frac{3}{8}$ x $\frac{4}{6}$

= $\frac{12}{48}$

= $\frac{1}{4}$

f. $\frac{7}{12}$ of $\frac{9}{14}$ = $\frac{7}{12}$ x $\frac{9}{14}$

= $\frac{63}{168}$

= $\frac{3}{8}$

2. $\frac{22}{6}$ x $\frac{3}{11}$ = $\frac{66}{66}$

= 1

b. $\frac{15}{6}$ x $\frac{4}{5}$ = $\frac{60}{30}$

= 2

c. $\frac{25}{8}$ x $\frac{4}{10}$ = $\frac{100}{80}$

= $\frac{5}{4}$

d. $\frac{33}{12}$ x $\frac{4}{15}$ = $\frac{132}{180}$

= $\frac{11}{15}$

4 0

3 years ago

4. What does doubling the voltage do to the strength of the electromagnet?

Naya [18.7K]

Answer:

it can make it stronger!

5 0

3 years ago

Read 2 more answers