hey there!
atomic mass cobalt = 58.9332 amu
therefore:
1 mol Co ------------ 58.9332 g
moles ------------ 50 g
moles = 50 x 1 / 58.9332
moles = 50 / 58.9332
= 0.8484 moles of Co
Hope this helps!
Answer:
77.14 atm of pressure should be of an acetylene in the tank.
Explanation:
According to reaction, 2 moles of acetylene reacts with 5 moles of oxygen.
Moles of oxygen=
Moles of acetylene =
Volume of large tank with oxygen gas,
Pressure of the oxygen gas inside the tank =
..[1]
Volume of small tank with acetylene gas ,
Pressure of the acetylene gas inside the tank =
..[2]
Considering both the gases having same temperature T, [1]=[2]
77.14 atm of pressure should be of an acetylene in the tank.
Answer : The amount of energy released would be,
Solution : Given,
Mass =
conversion : (1 Kg = 1000 g)
Speed of light =
Formula used :
where,
E = energy released
m = mass
c = speed of light
Now put all the given values in this formula, we get
Therefore, the amount of energy released would be,
Answer:
The reaction quatient Q is 0.306
Explanation:
Step 1: data given
Volume = 2.50 L
Temperature = 1100 K
Number of moles C = 6.75 moles
Number of moles H2O = 13.5 moles
Number of moles CO = 3.10 moles
Number of moles H2 = 9.00 moles
Step 2: The balanced equation
C(s)+H2O(g)⇌CO(g)+H2(g)
Step 3: Calculate the concentration
Concentration = moles / volume
[C] = 6.75 moles / 2.5 L
[C] = 2.7 M
[H20] = 13.5 moles / 2.5 L
[H2O] = 5.4 M
[CO] = 3.10 moles / 2.5 L
[CO] = 1.24 M
[H2] = 9.00 moles / 2.5 L
[H2]= 3.6 M
Step 4: Calculate Q
Q = [CO][H2] / [C][H2O]
Q = (1.24 * 3.6)/(2.7*5.4)
Q = 0.306
The reaction quatient Q is 0.306
I believe that this would be true