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Sergeu [11.5K]
3 years ago
13

Please help me, it's a simple equation

Physics
1 answer:
castortr0y [4]3 years ago
3 0

Because the elevator moves at a constant speed, it's in equilibrium and the net force acting on it is zero. Then the tension in the cable exactly equals the magnitude of the elevator's weight, which is

(3000 kg) (9.80 m/s²) = 29,400 N

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As they evolved and adapted, those of the fittest survived to reproduce. Those that did not adapt, died.
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Refraction occurs when light passing from one medium to another. True or False
kodGreya [7K]

Answer: True

Refraction is a phenomenon in which the light bends or changes its direction (and changes the speed of propagation, as well) <u>when passing through a medium</u> with a refractive index n <u>different from the other medium.  </u>

Where the Refractive index is a number that describes how fast light propagates through a medium or material:

n=\frac{c}{v}

Being n a relation between the speed of light in vacuum c  and its speed in the other medium v .

It is important to note that in this process, the wavelength may be modified because it depends on the medium, however, the refracted ray of light does not change its frequency.

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4 years ago
The displacement z of a particle of rest mass m0, resulting from a constant force m0g along the z-axis is including relativistic
Debora [2.8K]

Hi, your question was incomplete, hence I am writing down the complete question below.

Q)The displacement x of a particle of rest mass m0, resulting from a constant force m0g along the  x-axis, is

x= c2/g{[1+(gt/c)2]power0.5-1}

including relativistic effects. Find the displacement x as a power series in time t. Compare with  the classical result.

Answer:

<h3>Please refer to the attachment below.</h3>

Explanation:

<h3>Please refer to the attachment below for explanation.</h3>

3 0
3 years ago
A singly charged ion of 7Li (an isotope of lithium which lost only one electron) has a mass of 1.16 ×10^-26 kg. It is accelerate
MaRussiya [10]

Explanation:

It is given that,

Mass of lithium, m=1.16\times 10^{-26}\ kg

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Uniform magnetic field, B = 0.724 T

Applying the conservation of energy as :

\dfrac{1}{2}mv^2=qV

v=\sqrt{\dfrac{2qV}{m}}

q is the charge on an electron

v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\ C\times 224\ V}{1.16\times 10^{-26}\ kg}}

v = 78608.58 m/s

v=7.86\times 10^4\ m/s

To find the radius of the ion's path in the magnetic field. The centripetal force is balanced by the magnetic force as :

qvB=\dfrac{mv^2}{r}

r=\dfrac{mv}{qB}

r=\dfrac{1.16\times 10^{-26}\ kg\times 7.86\times 10^4\ m/s}{1.6\times 10^{-19}\ C\times 0.724\ T}

r = 0.0078 meters

So, the radius of the path of the ion is 0.0078 meters. Hence, this is the required solution.

4 0
3 years ago
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