Answer:
D) The element is most likely from Group 6A or 7A and in period 2 or 3.
Explanation:
Electronegativity of an atom is the tendency of an atom to attract shared paired of electron to itself. Electronegativity increase across the period from left to right.The ability of an atom to attract electron to itself is electronegativity. Group 7A and 6A elements can easily attract atoms to itself so they are highly electronegative. The most electronegative element in the periodic table is fluorine.Group 6A and 7A is likely to have high electronegativity.
Electron affinity of an atom is the amount of energy release when an atom gains electron . Generally, when atom gains electron they become negatively charged. Group 6A and 7A elements have high electron affinity.
Ionization energy is the energy required to remove one or more electron from a neutral atom to form cations. ionization energy of group 7A and 6A are usually high because the energy required to remove these electron is usually very high . The elements in this groups usually gain electron easily so the energy to remove electron is very high.
Explanation:
Orbital period = 2 x 10⁶s
Total radius = 2.5 x 10¹²m
Unknown:
Tangential speed of the satellite = ?
Solution:
The tangential speed simply expresses the rate at which the distance moves around its orbit with time.
Since the orbit is taken to be circular;
Tangential speed = 
r is the radius
t is the time or orbital radius
Tangential speed =
}[/tex]
Tangential speed = 7.85 x 10⁶m/s
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Answer: wool, rubber, & plastic
Explanation: Insulators slow transfer.
Answer:
Total displacement 155 m
Explanation:
From the question, the formula to apply will be that of cosine rule where:

where
a= 43 m , b=130m and c =? , <C=28° + 90° =118°
Substituting values in the equation as;


Answer: 9.08KW and 16.21KW
Explanation:
The convection over a flat surface with a length of 10 m and a width of 6m.
The mean temperature is (5oC + 12oC)/2 = 8.5oC.
Then find the following properties of air at this temperature from Table A-15:
k = 0.02428 W/m(oC, v= 1.413x10-5 m2/s, and Pr = 0.7340.
find the Reynolds number. Re= VL/v
Check screenshot
This means that the flow becomes turbulent over the plate and we can use the Nusselt number equation for combined laminar and turbulent flow.
Check screenshot
We then use this Nusselt number to find the heat transfer coefficient and the heat transfer.
Check the screen shot for the calculation
Ans
9.08 kW
Then if the wind velocity were doubled, the Re number would be doubled and we would repeat the calculations above, starting with this revised Reynolds number..
Ans
16.21 kW