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scoundrel [369]
3 years ago
11

Three boys of equal strength try to break a rope (and fail) by tying one end to a fence post and tugging on the other end. Three

additional boys (about the same strength as the others) come along and offer their assistance. Which of the following will maximize the tension in the rope?
A. It does not matter: the rope sustains the same tension in both cases.
B. Untie the rope from the post and have three boys tug on one end and the remaining three on the other (like a tug- of-war)
C. Keep one end of the rope tied to the post and have all six boys tug on the other end.
Physics
1 answer:
podryga [215]3 years ago
4 0

The best choice would be C. Keep one end of the rope tied to the post and have all six boys tug on the other end.

Reason:

A is not correct since in the first case which is B, untying the rope from the post and have 3 boys on each end of it tug, will provide equal or a near equal amount of tension since the boys are all within the same strength, however there can be variables that will affect the tension.

That means B would be true according to A, and then for C, having all six boys pull on the other end of the rope would provide greater tension, since if 3 boys of the same strength range can't break the rope when its tied to the fence, we add the other 3 boys of the same strength.

However, if 3 boys are on each end of the rope and of the same strength then the rope will not break since there is an equal amount of net force exerted on the rope.

We know that the fence can withstand the strength of 3 boys but if we add the other 3 boys then it could provide us with a different outcome.

3B < F

3B(2) ≥ F

So, therefore, our best choice would be C since A and B is incorrect.

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16 kilometers is the answer i came up with. hope this helps.
4 0
3 years ago
How is the phenomenon of reflection used in making a kaleidoscope​
dusya [7]

Answer:

The kaleidoscope

Explanation:

gives a number of images formed by reflection from the mirrors inclined to one another. Designers and artists use kaleidoscope to get ideas for new patterns to design wallpapers, jewellery and fabrics.

8 0
3 years ago
Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p
boyakko [2]

Answer:

The number of free electrons per cubic meter is 7.61\times 10^{28}\ m^{-3}

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, \sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}

Density of metal, \rho=10.5\ g/cm^3

Atomic weight, A = 107.87 g/mol

Let n is the number of  free electrons per cubic meter such that,

n=1.3\ N

n=1.3(\dfrac{\rho N_A}{A})

Where

\rho is the density of silver atom

N_A is the Avogadro number

A is the atomic weight of silver

n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})

n=7.61\times 10^{22}\ cm^{-3}

or

n=7.61\times 10^{28}\ m^{-3}

Hence, this is the required solution.

6 0
3 years ago
The planets eccentricity in order least to greatest​
ankoles [38]

Answer:

Orbital Eccentricity

Planet Orbital Eccentricity

(Point in Orbit Closest to Sun)

measured in AU's

Mercury 0.206

Venus 0.007

Earth 0.017

Mars 0.093

Jupiter 0.048

Saturn 0.056

Uranus 0.047

Neptune 0.009

Pluto 0.248

Explanation:

link to information:

https://www.enchantedlearning.com/subjects/astronomy/glossary/Eccentricity.shtml

3 0
2 years ago
Lightweight, vertically suspended spiral spring with a spring constant of 8.6 N / m is fitted with 64 g weight. The weight shall
alexandr1967 [171]

Answer:

Explanation:

Given that

Force constant k=8.6N/m

Weight =64g=64/1000=0.064kg

Extension is 45mm=45/1000= 0.045m

It will have it highest spend when the Potential energy is zero

Therefore energy in spring =change in kinetic energy

Ux=∆K.e

½ke² = ½mVf² — ½mVi²

Initial velocity is 0, Vi=0m/s

½ke² = ½mVf²

½ ×8.6 × 0.045² = ½ ×0.064 ×Vf²

0.0087075 = 0.032 Vf²

Then, Vf² = 0.0087075/0.032

Vf² = 0.2721

Vf=√0.2721

Vf= 0.522m/s

The time it will have this maximum velocity?

Using equation of motion

Vf= Vi + gr

0.522= 0+9.81t

t=0.522/9.81

t= 0.0532sec

t= 53.2 milliseconds

5 0
2 years ago
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