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SVEN [57.7K]
3 years ago
15

Freight trains can produce only relatively small accelerations and decelerations. What is the final velocity, in meters per seco

nd, of a freight train that accelerates at a rate of 0.065 m/s^2 for 9.75 min, starting with an initial velocity of 3.4 m/s? If the train can slow down at a rate of 0.625 m/s^2, how long, in seconds, does it take to come to a stop from this velocity? How far, in meters, does the train travel during the process described in part (a)? How far, in meters, does the train travel during the process described in part (b)?
Physics
1 answer:
Crank3 years ago
7 0

Answer:

Explanation:

Initial velocity of train u = 3.4 m⁻¹ , Acceleration a = .065 ms⁻² ,

time t = 9.75 x 60 = 585 s.

v = u + at

= 3.4 + .065 x 585

= 41.425 m / s

distance travelled during the acceleration ( s )

s = ut + 1/2 at²

= 3.4 x 585 + .5 x .065 x 585²

= 1989 + 11122.31

= 13111.31 m .

again for slowing process

u = 41.425 m / s

v = u -at

0 = 41.425 - 0.625 t

t = 66.28 s

v² = u² - 2as

0 = 41.425² - 2 x .625 s

s = 1372.82 m

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Y_Kistochka [10]

Answer:

7.92 m/s

Explanation:

m_1 = Mass of raindrop = 45m_2

m_2 = Mass of mosquito

u_1 = Initial Velocity of raindrop = 8.1 m/s

u_2 = Initial Velocity of mosquito = 0 m/s

v = Velocity of center of mass

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{45m_2\times 8.1 + m_2\times 0}{45m_2 + m_2}\\\Rightarrow v=\frac{364.5m_2}{46m_2}\\\Rightarrow v=7.92\ m/s

Hence, the velocity of the attached mosquito, falling immediately afterward is 7.92 m/s

4 0
3 years ago
What is characteristic of both sound waves and
REY [17]
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5 0
4 years ago
Read 2 more answers
To find the number of neutrons in an atom, you would subtract
larisa86 [58]

To find the number of neutrons in an atom, what we must do is to follow the following steps:

1) Find the element in the periodic table.

2) Find the atomic number of the element. The atomic number is the number of protons of a single atom of that element.

3) Find the atomic weight of the element.

4) Finally, we look for the number of neutrons. For this, we follow the following relationship:

Atomic weight - number of protons = number of neutrons.

Answer:

To find the number of neutrons in an atom, you would subtract:

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7 0
3 years ago
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Cell phone conversations are transmitted by high-frequency radio waves. Suppose the signal has wavelength 36.5 cm while travelin
tia_tia [17]

Answer:

f=8.219*10^{8}Hz

Explanation:

We are going to use the formula  v=fλ

Where v= velocity of radio waves

f= frequency

λ= wavelength of wave

  • radio waves are electromagnetic waves and as such they have the speed of light which is 3*10^{8}m/s.
  • also when a wave travels from one medium to another, the wavelength changes while the frequency remains the same.
  • calculating for the frequency of the wave in air also gives us the frequency in the window glass.

f=\frac{v}{λ}

v=3*10^{8}m/s.

λ=36.5 cm = 36.5/100= 0.365m

f=\frac{3*10^{8}m/s.}{0.365m}

f=8.219*10^{8}Hz

7 0
4 years ago
A muscle inserts 1.5 cm from the joint axis and exerts 300 N of force at an angle of pull of 60 degrees. How much torque is prod
Amanda [17]

Answer:

torque = 3.897 N-m

Explanation:

given data

force = 300 N

angle = 60 degree

distance = 15 cm

to find out

torque

solution

we will apply here torque formula that is given below

torque = force × sinθ × distance    ...................1

put here all these value in equation 1

we get torque

torque  = force × sinθ × distance

torque  = 300 × sin60 × 1.5 ×10^{-2}

torque  = 300 × 0.8660 × 1.5 ×10^{-2}

torque  = 259.80 × 1.5 ×10^{-2}

torque  = 389.711 ×10^{-2}

torque = 3.897 N-m

8 0
3 years ago
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