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SVEN [57.7K]
3 years ago
15

Freight trains can produce only relatively small accelerations and decelerations. What is the final velocity, in meters per seco

nd, of a freight train that accelerates at a rate of 0.065 m/s^2 for 9.75 min, starting with an initial velocity of 3.4 m/s? If the train can slow down at a rate of 0.625 m/s^2, how long, in seconds, does it take to come to a stop from this velocity? How far, in meters, does the train travel during the process described in part (a)? How far, in meters, does the train travel during the process described in part (b)?
Physics
1 answer:
Crank3 years ago
7 0

Answer:

Explanation:

Initial velocity of train u = 3.4 m⁻¹ , Acceleration a = .065 ms⁻² ,

time t = 9.75 x 60 = 585 s.

v = u + at

= 3.4 + .065 x 585

= 41.425 m / s

distance travelled during the acceleration ( s )

s = ut + 1/2 at²

= 3.4 x 585 + .5 x .065 x 585²

= 1989 + 11122.31

= 13111.31 m .

again for slowing process

u = 41.425 m / s

v = u -at

0 = 41.425 - 0.625 t

t = 66.28 s

v² = u² - 2as

0 = 41.425² - 2 x .625 s

s = 1372.82 m

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Answer:

Frequency

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3 years ago
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2 years ago
WILL MARK AS BRAINLIEST IF CORRECT ANSWERS PLZ HELP 15 PTS!!!!!!
nlexa [21]

Question 9 is 100 N.

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3 years ago
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HOLA, NECESITO AYUDA!
givi [52]

The electrostatic force between the two ions is 2.9\cdot 10^{-10} N

Explanation:

The electrostatic force between two charged particle is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

In this problem, the ion of sodium has a charge of

q_1 = +e = +1.6\cdot 10^{-19} C

while the ion of chlorine has a charge of

q_2 = -e = -1.6\cdot 10^{-19}C

And the distance between the two ions is

r=282 pm = 282\cdot 10^{-12} m

Substituting, we find the electrostatic force between the two ions:

F=(8.99\cdot 10^9) \frac{(1.6\cdot 10^{-19})(-1.6\cdot 10^{-19})}{(282\cdot 10^{-12})^2}=-2.9\cdot 10^{-10} N

where the negative sign simply means that the force is attractive, since the two ions have opposite charge.

Learn more about electrostatic force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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2 years ago
If an object is thrown in an upward direction from the top of a building 160 ft high at an initial speed of 30 mi/h, what is
expeople1 [14]

Answer:

We can use  2 g H = v2^2 - v1^2    or

v2^2 = 2 g H + v1^2

Since 88 ft/sec = 60mph   we have 30 mph = 44 ft/sec

The object will return with the same speed that it had initially so the object

starts out with a downward speed of 44 ft/sec

Then v2^2 = 2 * 32 ft/sec^2 * 160 ft + 44 (ft/sec)^2

v2^2 = (2 * 32 * 160 + 44^2) ft^2 / sec^2 = 12180 ft^2/sec^2

v2 = 110 ft/sec

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2 years ago
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