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3 years ago

10

20 points!

2 answers:

fgiga [73]3 years ago

5 0

The pitch of a sound is determined by its frequency and its effect on the wave. This is known as the Doppler Effect. The pitch of a sound is related to the frequency of the sound wave.

I had this assignment and got a great score, good luck! Also I love your profile picture, Magnus Bane, right?

Flauer [41]3 years ago

3 0

<u>The frequency of the sound</u> determines the pitch .The higher the frequency , the more high pitched it will sound. if the frequency is very low, it will sound very low pitched.

This is affected by motion of a sound source because if the sound source moves faster, this makes the frequency higher( since frequency is the number of waves/revolutions/whatever per second)

So , if for example , the sound source makes 4 vibrations or whatever in a second , it will have a frequency of 4Hz , but if a sound source makes 8 vibrations or whatever in a second , it will have a frequency of 8Hz . And since pitch is determined by frequency , the sound pitch with a frequency of 8Hz will have a higher pitch than sound source with a frequency of 4Hz.

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A horizontal desk surface measures 1.7 m by 1.0 m. If the Earth's magnetic field has magnitude 0.42 mT and is directed 68° below

AlexFokin [52]

Answer:

The magnetic flux through the desk surface is $6.6\times10^{-4}\ T-m^2$ .

Explanation:

Given that,

Magnetic field B = 0.42 T

Angle =68°

We need to calculate the magnetic flux

$\phi=BA\costheta$

Where, B = magnetic field

A = area

Put the value into the formula

$\phi=0.42\times10^{-3}\times1.7\times1.0\cos22^{\circ}$

$\phi=0.42\times10^{-3}\times1.7\times1.0\times0.927$

$\phi=6.6\times10^{-4}\ T-m^2$

Hence, The magnetic flux through the desk surface is $6.6\times10^{-4}\ T-m^2$ .

3 0

3 years ago

What acceleration will you give to a 24.5 kg

Ludmilka [50]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

$\boxed{F=ma}$

<u>Δ Being Δ</u>

F = Force = 78,3 N

m = Mass = 24,5 kg

a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

$\boxed{a=78,3\ N / 24,5\ kg}$

⇒ Resolving

$\boxed{a=3.19\ m/s^{2}}$

Result:

The aceleration is <u>3,19 meters per second squared (m/s²)</u>

Good Luck!!

4 0

3 years ago

An ideal spring is hung vertically from the ceiling. The spring constant is k = 125 N/m. A block of mass m = 650 g (1000 g = 1 k

Brrunno [24]

Answer:

0.102 m

Explanation:

k = spring constant of the spring = 125 N/m

m = mass of the block attached to the spring = 650 g = 0.650 kg

x = maximum extension of the spring

h = height dropped by the block = x

Using conservation of energy

Spring potential energy gained = Gravitational potential energy lost

(0.5) k x² = mgh

(0.5) k x² = mgx

(0.5) (125) x = (0.650) (9.8)

x = 0.102 m

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