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Ksenya-84 [330]
3 years ago
10

Rank these oligonucleotides according to distance traveled in an electrophoretic separation

Chemistry
1 answer:
WINSTONCH [101]3 years ago
4 0
The larger the oligonucleotide, the less distance it will travel. Therefore, in the order of decreasing distance traveled:
AAACT → AGGGAAG → CTACGTGCG → TTTGCGTATTT → <span>GTATGTTCACCCGTC</span>
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If the temperature of a 5 L sample of gas is lowered from 400k to 200k, what will the resulting volume of the gas be?
FrozenT [24]

The answer would be 2.5ML

4 0
3 years ago
Calculate the following:<br> 36,000 nanograms =<br> micrograms
Alenkinab [10]
36 micrograms is the answer
7 0
3 years ago
When 1 mol of a fuel burns at constant pressure, it exchanges-3452 kJ of heat and does-11 kJ of workon the surroundings. What ar
Degger [83]

Answer:-3463 kJ and -3452kJ

Explanation:

ΔU is the change in internal energy of a system and its formula is;

ΔU = q + w

Where q represents heat transferred into or out of the system. Its value is positive when heat is transfer into the system and negative when heat is produced by the system.

W represents the work done on or by the system. Its value is positive when work is done on the system and negative when it is done by the system.

For the system in this question, we see that it produces heat which means heat is transferred out of the system, therefore the value of q is negative, it can also be seen that work is done by the system which means that w is also negative.

Therefore,

ΔU = -q-w

ΔU = -3452 kJ – 11kJ

= - 3463kJ

ΔH is the change in the enthalpy of a system and its formuls is;

ΔH = ΔU + Δ(PV)

By product rule Δ(PV) becomes ΔPV + PΔV

At constant pressure ΔP = 0. Therefore,

ΔH = -q-w + PΔV

w is equals to PΔV, So:

ΔH = -q

ΔH = -3452kJ

6 0
3 years ago
What is the pressure of 2.20 mol of a gas stored in a 4.5 L container at a temperature of 170 K? (Use PV=nRT and R = 8.314 L∙kPa
algol13

Answer:

I don't know how can i do

Explanation:

please give me hint

7 0
2 years ago
What is the formula for potassium citrate and how do you find it?
oee [108]

Answer:

Potassium citrate (also known as tripotassium citrate) is a potassium salt of citric acid with the molecular formula K3C6H5O7.

Chemical formula: K3C6H5O7

Density: 1.98 g/cm3

Melting point: 180 °C (356 °F; 453 K)

Boiling point: 230 °C (446 °F; 503 K)

Explanation:

7 0
3 years ago
Read 2 more answers
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