Answer:
a. WATER CONTENT.
mass of water (MW)= 417g - 225g
Mw= 192g
M= (Mw / Ms)
M= [192/417]
M= 0.46
M= 46.0%
b. Void Ration (e)
To calculate the void ratio we must first calculate the volume of solids. Then we can find the volume of voids by subtracting the volume of solids from the total volume.
Ps= (Ms/Vs)=GsPw
Therefore
Vs= (Ms/GsPw)
Vs= (417/ 2.70*1000)
Vs= 0.154cm3
But V= Vv+Vs
Vv=V-Vs
e= (Vv/Vs)
Answer:By obey peoples propertice
Explanation:
Answer:
It was a power supply of a circuit that was horizontal of the ladder where they controlled the circuit.
Explanation:
The question is incomplete. We have to calculate :
a). the cutting force
b). volumetric metal removal rate, MRR
c). the horsepower required at the cut
d). if the power efficiency of the machine tool is 90%, determine the motor horsepower
Solution :
Given :
Cutting velocity (v) = 500 ft/min
= 500 x 12 in/min
= 6000 in/min
Feed , f = 0.025 in/rev
Depth of cut, d = 0.2 in
b). Volumetric material removal rate, MRR = v.f.d
= 6000 x 0.025 x 0.2
= 30 
c). Horsepower required = MRR x unit horsepower
= 30 x 1.6
= 48 hp
a). Cutting force,

(1 hp = 550 ft lbf /sec)
= 3168 lbf
d). Machine HP required


= 53.33 HP
A) Jason is correct because smaller wings can cut through air better.