Answer:
47.91 sec
Explanation:
it is given that 
at t=0 velocity =0 ( as it is given that it is starting from rest )
we have to find time at which velocity will be 3.3 
we know that 

integrating both side
---------------eqn 1
at t=o it is given that v=0 putting these value in eqn 1 c=0
so 
when v= 3.3 
t=
=47.91 sec
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Answer:
a) 
b) attached below
c) type zero system
d) k > 
e) The gain K increases above % error as the steady state speed increases
Explanation:
Given data:
Motor voltage = 12 v
steady state speed = 200 rad/s
time taken to reach 63.2% = 1.2 seconds
<u>a) The transfer function of the motor from voltage to speed</u>
let ;
be the transfer function of a motor
when i/p = 12v then steady state speed ( k1 ) = 200 rad/s , St ( time constant ) = 1.2 sec
hence the transfer function of the motor from voltage to speed
= 
<u>b) draw the block diagram of the system with plant controller and the feedback path </u>
attached below is the remaining part of the detailed solution
c) The system is a type-zero system because the pole at the origin is zero
d) ) k > 
Answer:The awnser is 5
Explanation:Just divide all of it