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3 years ago

Describe each occupation

Engineering

1 answer:

vitfil [10]3 years ago

5 0

Answer:

Carpenter — A carpenter is someone who works with wood. They build houses and make cabinets etc.

Logging — Loggers are people who cut trees. They use strong chain saws to cut trees.

Shipwrights — Shipwrights build, design, and repair all sizes of boats.

Wood Machinist — Wood Machinists repair and cut timber or any kind of wood for construction projects. They also operate woodworking machines, as their name suggest.

Furniture finishers — Furniture finishers shape, decorate, and restore damaged and worn out furniture.

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A compressor receives air at 290 K, 95 kPa and shaft work of 5.5 kW from a gasoline engine. It should deliver a mass flow rate o

aev [14]

Answer:

P2 = 3.9 MPa

Explanation:

Given that

T₁ = 290 K

P₁ = 95 KPa

Power P = 5.5 KW

mass flow rate = 0.01 kg/s

solution

with the help of table A5

here air specific heat and adiabatic exponent is

Cp = 1.004 kJ/kg K

and k = 1.4

work rate will be

W = m × Cp × (T2 - T1) ..........................1

here T2 = W ÷ ( m × Cp) + T1

so T2 = 5.5 ÷ ( 0.001 × 1.004 ) + 290

T2 = 838 k

so final pressure will be here

P2 = P1 × $(\frac{T2}{T1})^\frac{k}{k-1}$ ..............2

P2 = 95 × $(\frac{838}{290})^\frac{1.4}{1.4-1}$

P2 = 3.9 MPa

3 0

3 years ago

When you are configuring data deduplication, you must choose a usage type for the volume you are configuring. Which of the follo

Finger [1]

Answer:

1. General purpose file server.

2. Virtual Desktop Infrastructure Server.

3. Virtualized Backup Server.

All except : Database server

Explanation:

As a simple definition, we can tell, data deduplication is an elimination of redundant data in data set and storing only one copy of the same data. It is done by identifying double byte patterns through data analysis, removing double data and replacing it with reference pointed to stored, single piece of data.

6 0

4 years ago

A rectangular car-top carrier of 1.7-ft height, 5.0-ft length (front to back), and 4.2-ft width is attached to the top of a car.

Nataliya [291]

Answer:

$\Delta P =1.2 \frac{1.3}{2}(26.822m/s)^2 (4.2*1.7*(0.3048)^2)=13.88 hp$

Explanation:

We can assume that the general formula for the drag force is given by:

$D= C_D \frac{\rho}{2}V^2 A$

And we can see that is proportional to the area. On this case we can calculate the area with the product of the width and the height. And we can express the grad force like this:

$D_1 = C_{D1} \frac{\rho}{2}V^2 (wh)$

Where w is the width and h the height.

The last formula is without consider the area of the carrier, but if we use the area for the carrier we got:

$D_2 = C_{D2} \frac{\rho}{2}V^2 (wh+ A_{carrier})$

If we want to find the additional power added with the carrier we just need to take the difference between the multiplication of drag force by the velocity (assuming equal velocities for both cases) of the two cases, and we got:

$\Delta P = C_{D2} \frac{\rho}{2}V^2 (wh+ A_{carrier}) V- C_{D1} \frac{\rho}{2}V^2 (wh) V$

We can assume the same drag coeeficient $C_{D1}=C_{D2}=C_{D}$ and we got:

$\Delta P = C_{D} \frac{\rho}{2}V^2 (wh+ A_{carrier}) V- C_{D} \frac{\rho}{2}V^2 (wh) V$

$\Delta P = C_{D} \frac{\rho}{2}V^3 (A_{carrier})$

1.7 ft =0.518 m

60 mph = 26.822 m/s

In order to find the drag coeffcient we ned to estimate the Reynolds number first like this:

$R_E= \frac{Vl}{v}= \frac{26.822m/s*0.518 m}{1.58x10^{-4} Pa s}= 8.79 x10^{4}$

And the value for the kinematic vicosity was obtained from the table of physical properties of the air under standard conditions.

Now we can find the aspect ratio like this:

$\frac{l}{h}=\frac{5}{1.7}2.941$

And we can estimate the calue of $C_D = 1.2$ from a figure.

And we can calculate the power difference like this:

$\Delta P =1.2 \frac{1.3}{2}(26.822m/s)^2 (4.2*1.7*(0.3048)^2)=13.88 hp$

8 0

3 years ago

Using the formula XC=1/(2πfC) in your answer, how would a capacitor influence a simple DC series circuit?

Kisachek [45]

Answer:

jdjdbddifnifndjrnirnrinr

5 0

3 years ago

Coastal regions are often affected by nearby ocean currents. The map shows how different ocean currents affect the United States

Effectus [21]

Effect of Ocean currents on the Coastal regions are described below.

Explanation:

1.Ocean currents effects the temperature of the region they travel through. Warm currents increase the temperature of the coasts along which they move. Sea breezes that blow over warm currents get warmed in turn and absorb moisture. Then they carry the warmth and moisture to neighboring coastal areas.

2.When land borders the ocean, the currents of the ocean warm or cool it, depending on the nature of the particular current that flows by that land. In cases where a warm current flows along a particular coast, that coastal area will generally be warmer than it would otherwise be if it were landlocked.

3.They produce high and low tides along coastal regions.They move vertically pushing warm water and nutrients to the surface along coastal regions.

4.The circumpolar current merges the waters of the Atlantic, Indian, and Pacific Oceans and carries up to 150 times the volume of water flowing in all of the world's rivers.

5 0

4 years ago