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ipn [44]
3 years ago
9

Explain why the following acts lead to hazardous safety conditions when working with electrical equipmenta. Wearing metal ring o

r braceletsb. Being barefootc. Working on a damp concrete floord. Touching grounded conductors while working on electrical equipmente. Working on electrical equipment with sweaty hands
Engineering
1 answer:
Rus_ich [418]3 years ago
4 0

Answer:

Please find the answer in the explanation

Explanation:

In Engineering, safety is very essential and very important for all engineers to stick to.

A.) Wearing metal ring or bracelets.

When their is discharg of electrical charges, wearing of metal rings or braceletsb can allow charges to pass through them into the body which can eventually lead to electrical shock.

B.) Being barefoot

Being bare footed is very dangerous because someone can mistakenly step on naked wire which can lead to electrical shock.

C. Working on a damp concrete floor.

It is very hazardous to be working on a damp concrete floor because of the water moisture. It is very unsafe for any electrical job to be done on any wet area because water can conduct electricity which can lead to electrical shock.

d. Touching grounded conductors while working on electrical equipment

Grounded conductor can allow charges to flow through them. So, it is very unsafe to have them have contact with the body because of electrical charges.

e. Working on electrical equipment with sweaty hands

A sweaty hands contain some content of water which can conduct electricity and lead to electrical shock.

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A cylindrical metal specimen having an original diameter of 12.8 mm and gauge length of 50.80 mm is pulled in tension until frac
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Answer:

%Reduction in area = 73.41%

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Explanation:

Given

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Diameter at the point of fracture = 6.60 mm (0.260 in.)

Fractured gauge length = 72.14 mm.

%Reduction in Area is given as:

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%RA = ((12.8/2)² - 6.6/2)²)/(12.8/2)²

%RA = 0.734130859375

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((do) - (d1))/(d1)

do = 72.14mm, d1 = 50.80mm

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%RA = ((72.24) - (50.80))/(50.80)

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3 years ago
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A center-point bending test was performed on a 2 in. x d in. wood lumber according to ASTM D198 procedure with a span of 4 ft an
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b = 2 in ,  d = ?

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940.3 ksi = ( 288 * 10^4 / 2d^3 / 12 ) * d / 2

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schepotkina [342]

Answer:

n = 2.36

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n = 2.36

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