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3 years ago

Science help please!!!!!!!!!!!!!!!!!!!

Physics

2 answers:

nikitadnepr [17]3 years ago

6 0

Answer: the first one

Explanation:

Natalka [10]3 years ago

5 0

Answer and Explanation:

All solutions are mixtures...

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A steel cable lying flat on the floor drags a 20 kg block across a horizontal, frictionless floor. A 110 N force applied to the

sammy [17]

Answer:

The mass of the cable is 4.94 kg

Explanation:

It is given that,

Mass of the block, m = 20 kg

Force applied to the cable, F = 110 N

Speed of the block, v = 4.2 m/s

Distance, d = 2 m

Let a is the acceleration of the block. It can be calculated using the third equation of motion as :

$v^2-u^2=2ad$

$(4.2)^2-(0)^2=2a\times 2$

$a=4.41\ m/s^2$

Let m' is the mass of the cable. It can be calculated using the second law of motion as :

$m'=\dfrac{F}{a}-m$

$m=\dfrac{110\ N}{4.41\ m/s^2}-20$

m = 4.94 kg

So, the mass of the cable is 4.94 kg. Hence, this is the required solution.

5 0

3 years ago

A volleyball player bumps a ball across a net with the velocity and angle shown below. What is the maximum height of the ball?

Marrrta [24]

Answer:

D. 12.4 m

Explanation:

Given that,

The initial velocity of the ball, u = 18 m/s

The angle at which the ball is projected, θ = 60°

The maximum height of the ball is given by the formula

h = u² sin²θ/2g m

Where,

g - acceleration due to gravity. (9.8 m/s)

Substituting the values in the above equation

h = 18² · sin²60 / 2 x 9.8

= 18² x 0.75 / 2 x 9.8

= 12.4 m

Hence, the maximum height of the ball attained, h = 12.4 m

6 0

3 years ago

Mikes car can accelerate from 0 mph to 40mph in 5 seconds what is the acceeration of his car in miles per hour per second

Montano1993 [528]

40/5=8. His speed increases 8mph/second :)

8 0

3 years ago

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A 75.5-kg person puts on a life jacket, jumps into the water, and floats. The jacket has a volume of 3.38 x 10-2 m3 and is compl

Andreyy89

Answer:

Density of jacket will be $680.4733kg/m^3$

Explanation:

We know that weight of water displaced= buoyant force=weight of man

Now volume of water displaced $v=3.38\times 10^{-2}+6.42\times 10^{-2}=9.8\times 10^{-2}m^3$

Density of water $d=100kg/m^3$

So weight of water displaced $=9.8\times 10^{-2}\times 1000=98kg$

So weight of jacket = 98-75 = 23 kg

We have given volume of the jacket = $3.38\times 10^{-2}m^3$

So density of jacket $=\frac{mass}{volume}=\frac{23}{3.38\times 10^{-2}}=680.4733kg/m^3$

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3 years ago

What information is required to provide advanced warnings of severe weather conditions?

OlgaM077 [116]

<span>What type of severe weather, direction the weather, any significant weather that may cause death or property destruction, and what areas will be affected by the severe weather is the information that is required for advance warnings of severe weather conditions. </span>

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4 years ago

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