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Yuki888 [10]
3 years ago
13

As the average kinetic energy of the particles in a gas increases, which of the following occurs?

Physics
2 answers:
Mila [183]3 years ago
5 0
The temperature increases
lara31 [8.8K]3 years ago
5 0

a The temperature of the gas increases.

b The temperature of the gas decreases.

c The number of particles increases.

d The number of particles decreases.

A is the correct answer

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Monochromatic light of wavelength λ=620nm from a distant source passes through a slit 0.450 mm wide. The diffraction pattern is
Elan Coil [88]

Answer:

The intensity of light from the 1mm from the central maximu is  I = 0.822I_o

Explanation:

From the question we are told that

                         The wavelength is \lambda = 620 nm = 620 *10^{-9}m

                         The width of the slit is w = 0.450mm = \frac{0.45}{1000} = 0.45*10^{-3} m  

                          The distance from the screen is  D = 3.00m

                           The intensity at the central maximum is I_o

                          The distance from the central maximum is d_1 = 1.00mm = \frac{1}{1000} = 1.0*10^{-3}m

        Let z be the the distance of a point with intensity I from central maximum

Then we can represent this intensity as

                     I = I_o [\frac{sin [\frac{\pi * w * sin (\theta )}{\lambda} ]}{\frac{\pi * w * sin (\theta )}{\lambda } } ]^2

    Now the relationship between D and z can be represented using the SOHCAHTOA rule i.e

            sin \theta = \frac{z}{D}

           

if the angle between the the light at z and the central maximum is small

Then  sin \theta =  \theta

   Which implies that

              \theta = \frac{z}{D}

substituting this into the equation for the intensity

             I = I_o [\frac{sin [\frac{\pi w}{\lambda} \cdot \frac{z}{D}  ]}{\frac{\pi w z}{\lambda D\frac{x}{y} } } ]

given that z =1mm = 1*10^{-3}m

   We have that

              I = I_o [\frac{sin[\frac{3.142 * 0.45*10^{-3}}{(620 *10^{-9})} \cdot \frac{1*10^{-3}}{3} ]}{\frac{3.142 * 0.45*10^{-3}*1*10^{-3} }{620*10^{-9} *3} } ]^2

                 =I_o [\frac{sin(0.760)}{0.760}] ^2

                 I = 0.822I_o

               

 

4 0
3 years ago
Which example show harassment?
koban [17]

C. making fun of a peer because she is Asian

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4 0
4 years ago
Read 2 more answers
10. How is the mass number calculated for an element?
masya89 [10]
It’s B, the sum of protons and neutrons
5 0
3 years ago
Edwin hubble discovered that
dmitriy555 [2]
Edwin Hubble discovered the cosmos , he discovered that there were other galaxies other than the Milky Way.
5 0
4 years ago
A sample of iron receives 50.J of heat energy that raises the temperature of the iron
tatiyna

Answer: 0.02kg

Explanation:

The quantity of heat energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 50 joules

Mass of iron sample = ? (let unknown value be Z)

C = 100 J/kg°C

Φ = 25°C

Then, Q = MCΦ

50J = Z x 100 J/kg°C x 25°C

50J = 2500J/kg x Z

Z = (50J/2500J/kg)

Z = 0.02kg

Thus, the mass of the iron sample is 0.02kg

6 0
4 years ago
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