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Fofino [41]
2 years ago
14

- Scrap tire management is primarily regulated at the

Engineering
2 answers:
krek1111 [17]2 years ago
5 0

Answer:D

Explanation:

Scrap tire management is primarily regulated at the state

level.

kompoz [17]2 years ago
3 0

Scrap tire management is primarily regulated at the state level.

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How much metal can be removed from a cracked drum to restore surface
Alisiya [41]

Answer:sc

Explanation:

sc

7 0
2 years ago
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A 1-kW electric resistance heater submerged in 10-kg water is turned on and kept on for 15 min. During the process, 400 kJ of he
hichkok12 [17]

Answer:

ΔT=  11.94 °C

Explanation:

Given that

mass of water = 10 kh

Time t= 15 min

Heat lot from water = 400  KJ

Heat input to the water = 1  KW

Heat input the water= 1 x 15 x 60

                                =900 KJ

By heat balancing

Heat supply - heat rejected = Heat gain by water

As we know that heat capacity of water

C_p=4.187 \frac{KJ}{kg-K}

Q=mC_p\Delta T

Now by putting the values

900 - 400 = 10 x 4.187 x ΔT

So  rise in temperature of water ΔT=  11.94 °C

6 0
3 years ago
A distillation column is initially designed to separate a mixture of toluene and xylene at around ambient temperature (say, 100°
weeeeeb [17]

Answer:

Purchase cost= 87056

Bar module cost= 292725

Explanation:

solution is attached below

6 0
3 years ago
If you had a match and a lantern and a candle in the dark which one would you choose to light.
PSYCHO15rus [73]

Answer:

The match

Explanation:

You can light both the lantern and the candle if you light the match first.

I don't know of this is a homework question, but I answered it anyway :)

5 0
3 years ago
Read 2 more answers
t is desired to produce aligned carbon fiber-epoxy matric composite having a longitudinal tensile strength of 800 MPa. Given (a)
Nesterboy [21]

Answer:

The value of critical length = 3.46 mm

The value of volume of fraction of fibers = 0.43

Explanation:

Given data

\sigma_{T} =  800 M pa

D = 0.017 mm

L = 2.3 mm

\sigma_{f} = 5500 M pa

\sigma_{m} = 18 M pa

\sigma_c = 13.5 M pa

(a) Critical fiber length is given by

L_{c} = \sigma_{f} (\frac{D}{2 \sigma_{c} } )

Put all the values in above equation we get

L_{c} =5500 (\frac{0.017}{(2) (13.5)} )

L_{c} = 3.46 mm

This is the value of critical length.

(b).Since this  critical length is greater than fiber length Than the volume fraction of fibers is given by

V_{f} = \frac{\sigma_T - \sigma_m}{\frac{L\sigma_c}{D} - \sigma_m }

Put all the values in above formula we get

V_{f} = \frac{800-18}{\frac{(2.3)(13.5)}{0.017} - 18 }

V_{f} = 0.43

This is the value of volume of fraction of fibers.

3 0
3 years ago
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