Answer:
To fit text to a shape in Affinity Designer, make sure you have your text selected. Then, grab the Frame Text Tool and click on the shape. A blinking cursor will appear within the shape, indicating that you can begin typing. The text you type will be confined to the boundaries of the shape.
Explanation:
Answer:
class TriangleNumbers
{
public static void main (String[] args)
{
for (int number = 1; number <= 10; ++number) {
int sum = 1;
System.out.print("1");
for (int summed = 2; summed <= number; ++summed) {
sum += summed;
System.out.print(" + " + Integer.toString(summed));
}
System.out.print(" = " + Integer.toString(sum) + '\n');
}
}
}
Explanation:
We need to run the code for each of the 10 lines. Each time we sum numbers from 1 to n. We start with 1, then add numbers from 2 to n (and print the operation). At the end, we always print the equals sign, the sum and a newline character.
Answer:
the crown is false densty= 12556kg/m^3[/tex]
Explanation:
Hello! The first step to solve this problem is to find the mass of the crown, this is found using the weight of the crown in the air by means of the equation for the weight.
W=mg
W=weight(N)=31.4N
M=Mass
g=gravity=9.81m/S^2
solving for M
m=W/g
![m=\frac{31.4N}{9.81m/S^2}=3.2kg](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B31.4N%7D%7B9.81m%2FS%5E2%7D%3D3.2kg)
The second step is find the volume of crown remembering that when an object is weighed in the water the result is the subtraction between the weight of the object and the buoyant force of the water which is the product of the volume of the crown by gravity by density of water
![F=mg-\alpha V g](https://tex.z-dn.net/?f=F%3Dmg-%5Calpha%20%20V%20g)
Where
F=weight in water=28.9N
m=mass of crown=3.2kg
g=gravity=9.81m/S^2
α=density of water=1000kg/m^3
V= crown´s volume
solving for V
![V=\frac{mg-F }{g \alpha } =\frac{(3.2)(9.81)-28.9}{9.81(1000)} =0.000254m^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bmg-F%20%7D%7Bg%20%5Calpha%20%7D%20%3D%5Cfrac%7B%283.2%29%289.81%29-28.9%7D%7B9.81%281000%29%7D%20%3D0.000254m%5E3)
finally, we remember that the density is equal to the index between mass and volume
![\alpha =\frac{m}{v} =\frac{3.2}{0.000254} =12556kg/m^3](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cfrac%7Bm%7D%7Bv%7D%20%3D%5Cfrac%7B3.2%7D%7B0.000254%7D%20%3D12556kg%2Fm%5E3)
To determine the density of the crown without using the weight in the water and with a bucket we can use the following steps.
1.weigh the crown in the air and find the mass
2. put water in a cylindrical bucket and measure its height with a ruler.
3. Put the crown in the bucket and measure the new water level with a ruler.
4. Subtract the heights, and find the volume of a cylinder knowing the difference in heights and the diameter of the bucket, in order to determine the volume of the crown.
5. find density by dividing mass by volume
Answer:
18.75in
Explanation:
Modulus of elasticity = Stress/Strain
Since stress = Force/Area
Given
Force = 1000lb
Area = 0.75sqin
Stress = 1000/0.75
Stress = 1333.33lbsqin
Strain
Strain = Stress/Modulus of elasticity
Strain = 1333.33/5,000,000
Strain = 0.0002667
Also
Strain = extension/original length
extension = 0.005in
Original length = extension/strain
Original length = 0.005/0.0002667
Original length = 18.75in
Hence the original length of the rectangular bar is 18.75in
Answer:
Explanation:
ADT for an 2-D array:
struct array{
int arr[10];
}arrmain[10];
An application that stores an array with 1000 rows and 1000 columns, where less than 10,000 of the array values are non-zero. The two different implementations for such arrays that would be more space efficient than a standard two-dimensional array implementation requiring one million positions are :
1) struct array{
int *p;
}arr[1000];
2) struct array{
int *p;
}arr[1000];