If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is
F' = G (5m₁) (2m₂) / d²
F' = 10 Gm₁m₂ / d²
but this is really just F' = 10F. So J is the correct choice.
Reducing the amount of loops will cause a loss of strength, as the loops make the magnet stronger.
Answer:
The height of the cliff is, h = 78.4 m
Explanation:
Given,
The horizontal velocity of the projectile, Vx = 20 m/s
The range of the projectile, s = 80 m
The projectile projected from a height is given by the formula
<em> S = Vx [Vy + √(Vy² + 2gh)] / g
</em>
Therefore,
h = S²g/2Vx²
Substituting the values
h = 80² x 9.8/ (2 x 20²)
= 78.4 m
Hence, the height of the cliff is, h = 78.4 m
Answer:
Explanation:
1. An ideal ammeter has very small or almost zero resistance. As the resistance is small the maximum current can pass through the ammeter which it can read it.
2. An ideal voltmeter has very large or infinite resistance. As the resistance is very large so the maximum voltage drops across the resistor and gives the accurate reading.
Answer:
Pressure = 320 N/m²
Explanation:
Given the following data;
Force = 8000 Newton
Area = 25 m²
To find the pressure, we would use the following formula;
Pressure = force/area
Substituting into the formula, we have;
Pressure = 8000/25
Pressure = 320 N/m²
