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LenKa [72]
4 years ago
7

A gas quickly expands in an isolated environment. During the process, the gas exchanges no heat with its surroundings. The proce

ss is:
a. isobaric
b. isotonic
c. isothermal
d. isochoric
e. adiabatic
Chemistry
1 answer:
AysviL [449]4 years ago
6 0

Answer:

e. adiabatic process

Explanation:

Adiabatic process  -

In the thermodynamic system , an adiabatic process is the one which involves no transfer of mass or heat of the substance , is referred to adiabatic process.

In this process , the temperature need not be constant ,

But only the heat is transferred into or out of the system .

Hence, from the given information of the question,.

The correct option is e. adiabatic process .

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2. How many calories are needed to raise 50 g of iron from 55°C to 200°C? (c = 0.110 cal/g °C)
lord [1]

Answer:

Q = 797.5 cal

Explanation:

Given that,

Mass of iron, m = 50 g

The temperature rises from 55°C to 200°C.

We need to find the heat needed to raise the temperature. The heat raised is given by :

Q=mc\Delta T

Put all the values,

Q=50\times 0.11\times (200-55)\\\\Q=797.5\ cal

So, 797.5 calories of heat is needed.

3 0
3 years ago
Which elements can form acidic compounds? Check all that apply. sulfur rubidium arsenic selenium silicon xenon antimony
Archy [21]

The correct answer is Sulfur, Arsenic, selenium, silicon, and antimony.

6 0
3 years ago
Read 2 more answers
Gaseous methane ch4 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 14.0
never [62]
<span>2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
I know I got this wrong</span>
6 0
4 years ago
How many moles of MgCl2 are there in 319 g of the compound?
Leokris [45]

Hey there!:

Molar mass MgCl2 = 95.2110 g/mol

So:

1 mole MgCl2 -------------- 95.2110 g

moles MgCl2 ---------------- 319 g

moles MgCl2 = 319 * 1 / 95.2110

moles MgCl2 = 319 / 95.2110

=> 3.350 moles of MgCl2


Hope that helps!

3 0
3 years ago
Suppose you made 40 atoms of Highlinium and it has a
Karo-lina-s [1.5K]

Answer:

After 6sec 5 atoms will be left.

Explanation:

Given data:

Total atoms of Highlinium = 40

Half life = 2 sec

Atoms left after 6sec = ?

Solution:

First of all we will calculate the number of half lives passes during 6sec.

Number of half lives = Time elapsed/ half life

Number of half lives = 6 sec / 2sec

Number of half lives = 3

Now we will calculate the number of atoms left

At time zero = 40 atoms

At 1st half life = 40 atoms/2 = 20 atoms

At 2nd half life = 20 atoms/2 = 10 atoms

At 3rd half life = 10 atoms / 2 = 5 atoms

Thus, after 6sec 5 atoms will be left.

6 0
3 years ago
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