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LenKa [72]
3 years ago
7

A gas quickly expands in an isolated environment. During the process, the gas exchanges no heat with its surroundings. The proce

ss is:
a. isobaric
b. isotonic
c. isothermal
d. isochoric
e. adiabatic
Chemistry
1 answer:
AysviL [449]3 years ago
6 0

Answer:

e. adiabatic process

Explanation:

Adiabatic process  -

In the thermodynamic system , an adiabatic process is the one which involves no transfer of mass or heat of the substance , is referred to adiabatic process.

In this process , the temperature need not be constant ,

But only the heat is transferred into or out of the system .

Hence, from the given information of the question,.

The correct option is e. adiabatic process .

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Suppose you have a liquid solution containing two components, acetone and nonane. The boiling point of pure acetone is 56 C and
Tom [10]

Answer:

The boiling point is somewhere between 56 and 151 °C

Explanation:

Hello,

In this case, it is possible to compute it via rigorous methods in phase equilibrium by using for example a cubic equation of state to model the vapor phase and a suitable excess Gibbs free energy model for the liquid phase, nonetheless, it is an arduous task. In such a way, since the information about both acetone's and nonane's pure boiling points is given as well as acetone's mole fraction, which points out it is about a binary liquid solution, one could make up the boiling point is somewhere between 56 and 151 °C precising that it should be closer to 151 °C as the mixture is 90% nonane and 10% acetone.

Best regards.

4 0
3 years ago
How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g
Serhud [2]

<u>Answer:</u> The energy released for the decay of 3 grams of 230-Thorium is 2.728\times 10^{-15}J

<u>Explanation:</u>

First we have to calculate the mass defect (\Delta m).

The equation for the alpha decay of thorium nucleus follows:

_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

\Delta m=(m_{Ra}+m_{He})-(m_{Th})

\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg

(Conversion factor: 1amu=1.66\times 10^{-27}kg )

To calculate the energy released, we use Einstein equation, which is:

E=\Delta mc^2

E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2

E=2.0916\times 10^{-13}J

The energy released for 230 grams of decay of thorium is 2.0916\times 10^{-13}J

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = 2.0916\times 10^{-13}J

Then, 3 grams of Th will release energy of = \frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J

Hence, the energy released for the decay of 3 grams of 230-Thorium is 2.728\times 10^{-15}J

5 0
3 years ago
To determine the specific heat capacity of copper, Alyssa performed an investigation by which she dropped a heated piece of copp
user100 [1]

Answer:

0.446

Explanation:

ccu =  3035.655 / 104 g x (98.9 - 33.5)  = 0.446 J / g 0 C

6 0
2 years ago
H2S (g) + O2(g) -&gt; SO2+ H2O, how many grams of O2 are needed to make 25.0 g of SO2 (Hint: balance the equation first)
vekshin1

Answer:

Hello

The answer is 18,7(b)

Explanation:we don't know the value of o² so at first we should put (x)instead of gr of o²and then write 1molO²/32grO²×2mol SO²/3mol O²×64gr SO²/1molSO²=25 gr SO².and then just find the value of (x).

5 0
3 years ago
Why is carbon tetrachloride a liquid at room temperature
miv72 [106K]
Because I'm the warm it melts in the cold it's frozen
3 0
3 years ago
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