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____ [38]
4 years ago
10

Is the force of gravity stronger on a piece of paper when it is crumpled? is the force of gravity stronger on a piece of iron th

an it is on a piece of wood, if they both have the same mass?
Physics
1 answer:
Kipish [7]4 years ago
5 0

No, gravity pulls every object with the same force irrespective of its shape, size place etc.

Therefore the force of gravity on the iron and wooden piece of same mass is same. Also the force of gravity is same on the crumpled piece of paper as that of plain paper.

Force of gravity is always same.

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Help please asap I'm super lost
vaieri [72.5K]
A compound is two or more elements combinded together.
A element is a pure substance.
it looks like all of them are compounds except the carbon dixode, My teacher would accept that as a anwser idk bout urs thoughs.
6 0
3 years ago
Read 2 more answers
1. An automobile traveling at 25 km/hour has kinetic energy equal to 1x 10^4J.
aleksandrvk [35]

Explanation:

It is given that,

Speed of an automobile is 25 km/h or 6.95 m/s

Kinetic energy of the automobile is 10^4\ J

(a) Kinetic energy of automobile s given by :

K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 10^4}{(6.95)^2}\\\\m=414\ kg

(b) If the velocity of the car is increased to 45 km/hour or 12.5 m/s, new kinetic energy becomes :

K=\dfrac{1}{2}\times 414\times (12.5)^2\\\\K=32343.75\ J

(c) If the velocity is increased to 80 km/hour, 22.23 m/s, So

K=\dfrac{1}{2}\times 414\times (22.23)^2\\\\K=102293.79\ J

Hence, this is the required solution.

3 0
4 years ago
A bicyclist initially at rest, begins pedaling and gained speed steadily for 4.80s during which she covers 37.0m What was her fi
lidiya [134]

Answer:

The final speed of the bicyclist is 15.44 m/s.

Explanation:

Given;

initial velocity, u = 0

time of motion, t = 4.8 s

distance covered, d = 37.0 m

The acceleration of the bicyclist is calculated as;

d = ut + ¹/₂at²

37 = 0 + ¹/₂(4.8)²a

37 = 11.52a

a = 37 / 11.5

a = 3.22 m/s²

The final speed of the bicyclist is given as;

v² = u² + 2ad

v² = 0 + 2(3.22)(37)

v² = 238.28

v = √238.28

v = 15.44 m/s

Therefore, the final speed of the bicyclist is 15.44 m/s.

4 0
3 years ago
A man stands on a platform that is rotating (without friction) with an angular speed of 1.2 rev/s; his arms are outstretched and
Savatey [412]

Answer:

resulting angular speed = 3.6 rev/s

Explanation:

We are given;

Initial angular speed; ω_i = 1.2 rev/s

Initial moment of inertia;I_i = 6 kg/m²

Final moment of inertia;I_f = 2 kg/m²

From conservation of angular momentum;

Initial angular momentum = Final angular momentum

Thus;

I_i × ω_i = I_f × ω_f

Making ω_f the subject, we have;

ω_f = (I_i × ω_i)/I_f

Plugging in the relevant values;

ω_f = (6 × 1.2)/2

ω_f = 3.6 rev/s

7 0
3 years ago
Where in the cell can you find the location of inherited traits?
sashaice [31]

Answer:

D.N.A

Explanation:

The d.n.a is where all the heriditary information is stored.

5 0
3 years ago
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