Which formula can be used to calculate average speed (v) for steady motions?

A tugboat tows a ship at a constant velocity. The tow harness consists of a single tow cable attached to the tugboat at point A

Y_Kistochka [10]

Answer:

The tensions in $T_{BC}$ is approximately 4,934.2 lb and the tension in $T_{BD}$ is approximately 6,035.7 lb

Explanation:

The given information are;

The angle formed by the two rope segments are;

The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°

The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°

Therefore, we have;

The tension in rope segment BC = $T_{BC}$

The tension in rope segment BD = $T_{BD}$

The tension in rope segment AB = $T_{AB}$ = Pulling force of tugboat = 1200 lb

By resolution of forces acting along the line A_F gives;

$T_{BC}$ × cos(26.0°) + $T_{BD}$ × cos(21.0°) = $T_{AB}$ = 1200 lb

$T_{BC}$ × cos(26.0°) + $T_{BD}$ × cos(21.0°) = 1200 lb............(1)

Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;

$T_{BC}$ × sin(26.0°) + $T_{BD}$ × sin(21.0°) = 0...........................(2)

Which gives;

$T_{BC}$ × sin(26.0°) = - $T_{BD}$ × sin(21.0°)

$T_{BC}$ = - $T_{BD}$ × sin(21.0°)/(sin(26.0°)) ≈ - $T_{BD}$ × 0.8175

Substituting the value of, $T_{BC}$ , in equation (1), gives;

- $T_{BD}$ × 0.8175 × cos(26.0°) + $T_{BD}$ × cos(21.0°) = 1200 lb

- $T_{BD}$ × 0.7348 + $T_{BD}$ ×0.9336 = 1200 lb

$T_{BD}$ ×0.1988 = 1200 lb

$T_{BD}$ ≈ 1200 lb/0.1988 = 6,035.6938 lb

$T_{BD}$ ≈ 6,035.6938 lb

$T_{BC}$ ≈ - $T_{BD}$ × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb

$T_{BC}$ ≈ -4934.1733 lb

From which we have;

The tensions in $T_{BC}$ ≈ -4934.2 lb and $T_{BD}$ ≈ 6,035.7 lb.

8 0

3 years ago

If a person pulls back a rubber band on a slingshot without letting to go of it, what type of energy will the rubber band have?

Travka [436]

Answer:

Potential energy. Releasing it, the potential energy would convert into motion, kinetic energy.

Potential energy is when an object has some sort of potential eg. for motion such as in this example.

7 0

2 years ago

What component in a circuit does this symbol represent?

Andreas93 [3]

Answer:

The given symbol is of DC power source

Option A is incorrect because in ammeter a letter A is written inside a circle.

Similarly, Option B is incorrect because in voltmeter V is written inside a circle

Option C and D are incorrect

Option E is correct it is a DC power source.

It is a Dc power source the left hand side is positive side and the right line is the negative side.

5 0

2 years ago

Read 2 more answers

The Earth has mass ME and average radius RE. The Moon has mass MM and the average distance from the center of mass of the moon t

marusya05 [52]

Answer:

Moment of inertia of Earth about its own axis is given as

$I = 9.7 \times 10^{37} kg m^2$

Explanation:

Since Earth is considered as solid sphere

So we will have

$I = \frac{2}{5}M_eR_e^2$

so we will have

$I = \frac{2}{5}(5.97 \times 10^{24})(6.371 \times 10^6)^2$

so we have

$I = 9.7 \times 10^{37} kg m^2$

3 0

2 years ago

What happens when a sound wave passes from water to air?

s344n2d4d5 [400]

It slows down. The molecules/particles aren't as close together, resulting in slower movement.

4 0

2 years ago

Read 2 more answers