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harkovskaia [24]
3 years ago
7

Which formula can be used to calculate average speed (v) for steady motions?

Physics
1 answer:
Liono4ka [1.6K]3 years ago
3 0
I’m pretty sure it’s speed=distance/time
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Need diagram right? Post it
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HELP ME PLEASE WITH MY HOMEWORK ILL GIVE BRAINLIEST
nadezda [96]

Answer:  Mass

Explanation:

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The slider of mass m is released from rest in position A and slides without friction along the vertical-plane guide shown. Deter
Anuta_ua [19.1K]

The value of normal force as the slider passes point B is

  • 6 mg

The value of h when the normal force is zero

  • 3R/2

<h3>How to solve for the normal force</h3>

The normal force is calculated using the work energy principle which is applied as below

K₁ + U₁ = K₂

k represents kinetic energy

U represents potential energy

the subscripts 1,2 , and 3 = a, b, and c

for 1 to 2

K₁ + W₁ = K₂

0 + mg(h + R) = 0.5mv²₂

g(h + R) = 0.5v²₂

v²₂ = 2g(1.5R + R)

v²₂ = 2g(2.5R)

v²₂ = 5gR

Using summation of forces at B

Normal force, N  = ma + mg

N = m(a + g)

N = m(v²₂/R + g)

N = m(5gR/R + g)

N = 6mg

for 1 to 3

K₁ + W₁ = K₃ + W₃

0 + mgh = 0.5mv²₃ + mgR

gh = 0.5v²₃ + gR

0.5v²₃ = gh - gR

v²₃ = 2g(h - R)

at C

for normal force to be zero

ma = mg

v²₃/R = g

v²₃ = gR

and v²₃ = 2g(h - R)

gR = 2gh - 2gR

gR + 2gR = 2gh

3gR = 2gh

3R/2 = h

Learn more about normal force at:

brainly.com/question/20432136

#SPJ1

8 0
1 year ago
A solenoid coil with 22 turns of wire is wound tightly around another coil with 330 turns. The inner solenoid is 21.0 cm long an
horsena [70]

Answer:

The average magnetic flux through each turn of the inner solenoid is 11.486\times10^{-8}\ Wb

Explanation:

Given that,

Number of turns = 22 turns

Number of turns another coil = 330 turns

Length of solenoid = 21.0 cm

Diameter = 2.30 cm

Current in inner solenoid = 0.140 A

Rate = 1800 A/s

Suppose For this time, calculate the average magnetic flux through each turn of the inner solenoid

We need to calculate the magnetic flux

Using formula of magnetic flux

\phi=BA

\phi=\dfrac{\mu_{0}N_{2}I}{l}\times\pi r^2

Put the value into the formula

\phi=\dfrac{4\pi\times10^{-7}\times330\times0.140}{21.0\times10^{-2}}\times\pi\times(\dfrac{2.30\times10^{-2}}{2})^2

\phi=11.486\times10^{-8}\ Wb

Hence, The average magnetic flux through each turn of the inner solenoid is 11.486\times10^{-8}\ Wb

7 0
3 years ago
4. show your understanding of electric and magnetic forces<br> below.
Vitek1552 [10]

Answer:

Explanation:

Electric forces exist among stationary electric charges; both electric and magnetic forces exist among moving electric charges. ... The magnetic force between two moving charges may be described as the effect exerted upon either charge by a magnetic field created by the other.

8 0
3 years ago
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