Answer:
Acceleration, 
Explanation:
It is given that,
Initial speed of the aircraft, u = 140 mi/h = 62.58 m/s
Finally, it stops, v = 0
Time taken, t = 2 s
Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :
So, the acceleration of the aircraft is 
and the car is decelerating. Hence, this is the required solution.
Answer:
The percentage of the weight supported by the front wheel is A= 19.82 %
Explanation:
B] Let the mass of plane be m, force on backwheels be Nb and nosewheel be Nn
Torque equation about nose wheel,
mg*(2.58-0.8) - Nb *(3.02-0.8) = 0
Nb = mg*(2.58-0.8)/(3.02-0.8) = 0.8018 mg
Nn = mg - Nb = (1-0.8018) mg = 0.1982mg
Weight percentage supported by front wheel = 19.82% answer
<span>When taking the reading you must see where the lower meniscus lies . The value at which the lower meniscus lies is your reading .</span>
Answer:
The value is 
Explanation:
From the question we are told that
The mass of matter converted to energy on first test is 
The mass of matter converted to energy on second test 
Generally the amount of energy that was released by the explosion is mathematically represented as
=> ![E = 1.5 *10^{-3} * [ 3.0 *10^{8}]^2](https://tex.z-dn.net/?f=E%20%3D%20%201.5%20%2A10%5E%7B-3%7D%20%20%2A%20%5B%203.0%20%2A10%5E%7B8%7D%5D%5E2)
=>
-- The acceleration of gravity is 9.8 m/s².
So if there's no air resistance, the speed of a falling object
always increases by 9.8 m/s for every second it falls.
Speed = (original speed) + (gravity x falling time)
-- If it has no vertical speed when it started, then at the end
of 3 seconds, its speed is
= (0) + (9.8 m/s² x 3 sec)
Velocity = 29.4 m/s downward .
