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3 years ago

What is the mechanical advantage of a pulley system that uses 280 N to lift a 320 Kg box 4.0 m in the air?

Physics

1 answer:

SVEN [57.7K]3 years ago

6 0

the force of effort is given as

E = effort force = 280 N

m = mass of box to be lifted = 320 kg

g = acceleration due to gravity = 9.8 m/s²

force of load due to weight of box is given as

L = force of load = mg

L = 320 x 9.8

L = 3136 N

mechanical advantage for pulley system is the simply the ratio of the effort put in to the load being lifted.

mechanical advantage is given as

MA = load/effort

MA = L/E

MA = 3136/280

MA = 11.2

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Answer:

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3 years ago

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3 years ago

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horrorfan [7]

Given that,

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Suppose the force is (2.00i + 9.00j + 5.30k) N, initial position is (2.70i - 2.90j + 5.50k) m and final position is (-4.10i + 3.30j + 5.40k) m.

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Put the value into the formula

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Using formula of work done

$W=F\cdot s$

Put the value into the formula

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Using formula of power

$P=\dfrac{W}{t}$

Where, P = power

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Put the value into the formula

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Using formula of angle

$\theta=\cos^{-1}(\dfrac{r_{1}r_{2}}{|r_{1}||r_{2}|})$

Put the value into the formula

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Hence, (a). The work done on the object by the force in the 5.40 s interval is 41.67 J.

(b). The average power due to the force during that interval is 7.71 Watt.

(c). The angle between vectors is 79.7°

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4 years ago