Answer:
Acceleration = 311.2 Km/hr²
Explanation:
Given: Radius of the Orbit r= 3.56 × 10⁶ km
Period of the orbit = 28 days = 672 hrs
Sol: We have Fc = MV²/r
⇒M ac = MV²/r
⇒ac = V²/r
First we have to Speed V so for this we have to find the circumference ( distance covered by the moon in one orbit)
⇒ Circumference= 2 π r
= 2 × 3.13149 × 3.56 × 10⁶ km
= 22,368,139.69 Km
Now Speed = Distance /time
Speed = 22,368,139.69 Km / 672 hrs
Speed V = 33,285.92 Km/Hr
Now
ac = V²/r = (33,285.92 Km/hrs)² / 3.56 × 10⁶ km
ac = 311.2 Km/hr²
Answer:
Velocity of electron will be 
Explanation:
We have given distance across the plate d = 2 mm 
Potential difference V = 6 volt
We know that potential difference at any distance is given by
V = Ed , here V is potential difference, E is electric field and d is distance
So 
Charge on electron 
We know that expression of velocity is given by
, here q is charge on electron, E is electric field and d is distance
So 
Answer: 
Explanation:
Given
Initial angular speed is 
Final angular speed is 
Time period 
Magnitude of the fan's acceleration is given by

Insert the values

Thus, fan angular acceleration is 
Answer:

Explanation:
The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

which is known as fundamental charge.
For an object containing N excess electrons, the total charge of the object is

In this problem, the number of excess electrons in the object is:

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:
