Two circular loops of wire, each containing a single turn, have the same radius of 5.10 cm and a common center. The planes of th
e loops are perpendicular. Each carries a current of 2.20 A. What is the magnitude of the net magnetic field at the common center?
1 answer:
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Answer:
m = 4.5021 kg
Explanation:
given,
Apparent mass of aluminium = 4.5 kg
density of air = 1.29 kg/m³
density of aluminium = 2.7 x 10⁷ kg/m³
true mass of the aluminium = ?
Weight in Vacuum
W = m g
W = ρV g
Air buoyancy acting on aluminium
B = ρ₀V g
Volume is the same in both cases since the volume of the aluminum
displaces an equal amount of volume air.
Apparent weight:
ρV g − ρ₀V g = 4.5 g
ρV − ρ₀V = 4.5
m = ρV
m = 4.5021 kg