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zloy xaker [14]
3 years ago
13

2. When carbohydrates are oxidized, the C-H bonds of the carbohydrate become C=O bonds of carbon dioxide. Oxidation is defined a

s a loss of electrons, but carbon does not become positively charged in the process. Why then is this considered oxidation?
A) The shared electrons in C-O bonds spend less time close to the carbon nucleus than the shared electrons in C-H bonds.
B) Electrons in the C=O bonds are higher energy than the electrons in the C-H bonds.
C) C=O bonds in CO2 are double bonds, and C-H bonds are single bonds.
D) The phosphate groups of ATP are ionized, and carbons donate those electrons.
Chemistry
1 answer:
Flauer [41]3 years ago
5 0

Answer:

A) The shared electrons in C-O bonds spend less time close to the carbon nucleus than the shared electrons in C-H bonds.

Explanation:

The electronegativity from H is 2.2, from C is 2.55 and from O is 3.44. This property is the measure of the attractive force between an atom and a pair of electrons.

So, the difference of electronegativity of H and C is smaller than the difference between O and C. Because oxygen is more electronegative, the electrons stay close to it in the bond C=O. So carbon has a partial positive charge in that bond. For the bond C-H, the shared electrons stay closes to carbon.

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A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h
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5.758  is the density of the metal ingot in grams per cubic centimeter.

Explanation:

1) Mass of pycnometer = M = 27.60 g

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2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' =  9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

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v'=19.73 cm^3-18.08 cm^3=

v'=1.65 cm^3

Since volume cannot be in negative .

Density of the metal =d'

=d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3

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