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zloy xaker [14]
3 years ago
13

2. When carbohydrates are oxidized, the C-H bonds of the carbohydrate become C=O bonds of carbon dioxide. Oxidation is defined a

s a loss of electrons, but carbon does not become positively charged in the process. Why then is this considered oxidation?
A) The shared electrons in C-O bonds spend less time close to the carbon nucleus than the shared electrons in C-H bonds.
B) Electrons in the C=O bonds are higher energy than the electrons in the C-H bonds.
C) C=O bonds in CO2 are double bonds, and C-H bonds are single bonds.
D) The phosphate groups of ATP are ionized, and carbons donate those electrons.
Chemistry
1 answer:
Flauer [41]3 years ago
5 0

Answer:

A) The shared electrons in C-O bonds spend less time close to the carbon nucleus than the shared electrons in C-H bonds.

Explanation:

The electronegativity from H is 2.2, from C is 2.55 and from O is 3.44. This property is the measure of the attractive force between an atom and a pair of electrons.

So, the difference of electronegativity of H and C is smaller than the difference between O and C. Because oxygen is more electronegative, the electrons stay close to it in the bond C=O. So carbon has a partial positive charge in that bond. For the bond C-H, the shared electrons stay closes to carbon.

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Table below shows the electronegativities of four elements. Which of the following bonds is the most polar?
Contact [7]

 Lets find the electronegativity difference between the bonded atoms;

C-H = 2.6-2.2 = 0.4

C-F = 4.0-2.6  = 1.4

F-F = 4.0-4.0   = 0

H-O = 3.4-2.2  = 1.2

Here the electronegativity difference is highest for C-F bond hence C-F bond is most polar.

8 0
4 years ago
A mixture of C3H8 and C2H2 has a mass of 2.8 g. It is burned in excess O2 to form a mixture of water and carbon dioxide that con
astraxan [27]

Answer:

The mass of C2H2 in the mixture is 0.56gram using the ratio of carbon in the products contributed by the C2H2.

Explanation:

The balanced equation for the reaction is: C3H8 + 2C2H2 + 10O2 >> 7CO2 + 6H2O.

From the reaction, we know that the oxygen was in excess, this will make the Carbon sources the limiting agents in the reaction. The details of the reaction showed that the ratio of water to the carbon dioxide is 1.6:1. This also means that the expected mole of carbon dioxide will be 7/1.6, which is 3.75moles.

The individual balanced equation of reaction is:

C3H3 +5O2 >> 3CO2 + 4H2O

and 2C2H2 + 5O2 >>4CO2 + 2H2O. From this one can quickly tell that the propane is in sufficient supply as it produces 3 moles of CO2 out of the expected 3.75 moles obtained above. Leaving 0.75moles of CO2 to the ethyne.

The mass of ethyne in the mixture will therefore be: 0.75/3.75 X 2.8 = 0.56g.

4 0
4 years ago
Could an organism survive without its mitochondria if all the other organelle were present
lisov135 [29]
No, <span>mitochondria convert the sugar, can give it(the cell) Nutrients (food) to mainly keep it fresh and alive. Without cells mitochondria can't do its job.</span>
8 0
4 years ago
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An organism that has been thriving, has died. Which of the following is NOT a cause of its demise? Question 6 options: appropria
pashok25 [27]

I would say soil would be your best option. This is because out of all these, soil collects a lot of different substances and could have easily absorbed something that then killed the organism.

6 0
3 years ago
Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
rewona [7]
<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

      = 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0
3 years ago
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