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4 years ago

Kim is cutting lengths of ribbon so that each length of ribbon equals 8 inches. How many centimeters does 8 inches equal

Physics

1 answer:

Aloiza [94]4 years ago

7 0

I think it's 96 because 1 inch = 12 centimeters so 8 multiply by 12 is 96 yah its 96

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An inclined plane can help _____.

mylen [45]

Reduce the effort needed to move a load vertically

5 0

3 years ago

An object accelerates 16.3 m/s2 when a force of 4.6 newtons is applied to it, what is the object in grams

stealth61 [152]

We have no idea WHAT the object is.

But if the 4.6 N is the ONLY force acting on it (including friction), then its mass is 282.2 grams.

6 0

3 years ago

A copper wire and a tungsten wire of the same length have the same resistance. What is the ratio of the diameter of the copper w

spayn [35]

Answer:

Therefore the ratio of diameter of the copper to that of the tungsten is

$\sqrt{3} :\sqrt{10}$

Explanation:

Resistance: Resistance is defined to the ratio of voltage to the electricity.

The resistance of a wire is

directly proportional to its length i.e $R\propto l$
inversely proportional to its cross section area i.e $R\propto \frac{1}{A}$

Therefore

$R=\rho\frac{l}{A}$

ρ is the resistivity.

The unit of resistance is ohm (Ω).

The resistivity of copper(ρ₁) is 1.68×10⁻⁸ ohm-m

The resistivity of tungsten(ρ₂) is 5.6×10⁻⁸ ohm-m

For copper:

$A=\pi r_1^2 =\pi (\frac{d_1}{2} )^2$

$R_1=\rho_1\frac{l_1}{\pi(\frac{d_1}{2})^2 }$

$\Rightarrow (\frac{d_1}{2})^2=\rho_1\frac{l_1}{\pi R_1 }$ ......(1)

Again for tungsten:

$R_2=\rho_2\frac{l_2}{\pi(\frac{d_2}{2})^2 }$

$\Rightarrow (\frac{d_2}{2})^2=\rho_2\frac{l_2}{\pi R_2 }$ ........(2)

Given that $R_1=R_2$ and $l_1=l_2$

Dividing the equation (1) and (2)

$\Rightarrow\frac{ (\frac{d_1}{2})^2}{ (\frac{d_2}{2})^2}=\frac{\rho_1\frac{l_1}{\pi R_1 }}{\rho_2\frac{l_2}{\pi R_2 }}$

$\Rightarrow( \frac{d_1}{d_2} )^2=\frac{1.68\times 10^{-8}}{5.6\times 10^{-8}}$ [since $R_1=R_2$ and $l_1=l_2$ ]

$\Rightarrow( \frac{d_1}{d_2} )=\sqrt{\frac{1.68\times 10^{-8}}{5.6\times 10^{-8}}}$

$\Rightarrow( \frac{d_1}{d_2} )=\sqrt{\frac{3}{10}}$

$\Rightarrow d_1:d_2=\sqrt{3} :\sqrt{10}$

Therefore the ratio of diameter of the copper to that of the tungsten is

$\sqrt{3} :\sqrt{10}$

8 0

4 years ago

A conductor is formed into a loop that encloses an area of 1.0 m2. The loop is orientedat a 30.0° angle with the xy-plane. A var

ivolga24 [154]

Answer:

29 T/s

Explanation:

Given:

Area enclosed by loop, A = 1 m²

Maximum induced emf, e = 25.0 V

loop is oriented at an angle 30° with the x-y plane.

varying magnetic field is oriented parallel to z-axis.

we have to find $\frac{dB}{dt}_{max}$

Induced emf is given by:

$e =-A.cos\theta .\frac{dB}{dt}\\ \Rightarrow \frac{dB}{dt}=-\frac{e}{Acos\theta} = -\frac{25}{1\times cos30^o} = -28.86T/s$ ≈29T/s

3 0

3 years ago

Two electrons are (20 mm) apart at closest approach. What is the magnitude of the maximum electric force that they exert on each

OLga [1]

Answer:

Answer is 5.76×10^-25.

Explanation:

Given values in the question are:

q = 1.6 x 10⁻¹⁹ C

k = 9 x 10⁹ N.m²/C²

Hence two points is 20mm apart so the radius becomes

R=0.02.

The formula is

F = kq^2/r^2

F= 9 x 10⁹× (1.6 x 10⁻¹⁹)^2 /(0.02)^2

F=5.76×10^-25.

6 0

3 years ago