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Mrrafil [7]
3 years ago
12

A hypothetical element x has 3 naturally occurring isotopes: 41.20% of 21x, with an atomic weight of 21.016 amu, 50.12% of 22x,

with an atomic weight of 21.942 amu, and 8.68% of 24x, with an atomic weight of 23.974 amu. on the basis of these data, calculate the average atomic weight of element x. report your answer to two decimal places.
Chemistry
1 answer:
iogann1982 [59]3 years ago
4 0
The average atomic weight is calculated by adding up the products of the percentage abundance and atomic weight. In this item, we have the equation,

     A = (0.412)(21.016 amu) + (0.5012)(21.942 amu) + (0.0868)(23.974 amu)

Simplifying the operation will give us the answer of 21.74 amu.

<em>Answer: 21.74 amu</em>
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Answer:

27 min

Explanation:

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v = \frac{vmax[S]}{Km + [S]}

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So, initially, the velocity of the formation of the substrate is 12μmol/9min = 1.33 μmol/min

If Km is a thousand times smaller then [S], then

v = vmax[S]/[S]

v = vmax

vmax = 1.33 μmol/min

For the new experiment, with one-third of the enzyme, the maximum velocity must be one third too, so:

vmax = 1.33/3 = 0.443 μmol/min

Km will still be much smaller then [S], so

v = vmax

v = 0.443 μmol/min

For 12 μmol formed:

0.443 = 12/t

t = 12/0.443

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katrin [286]

Answer:

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The compound Magnesium chloride is an ionic compound . The bond between an atom of magnesium and 2 atoms of chlorine is an ionic bonding.

The valency electron of magnesium is 2 electron , for the atom of magnesium to  attain octet rule, it will easily lose it 2 electrons to the chlorine atoms.

The chlorine atom on the other hand has 7 valency electrons, to attain octet configuration it will most likely gain 1 electron to become stable.

The magnesium atom loses 2 electron to the 2 atoms of chlorine. The 7 valency electrons of each chlorine atom will now be 8 to attain stable configuration. The final compound is written as MgCl2.

7 0
3 years ago
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mixas84 [53]

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