The structural formula of a chemical compound is a <u>graphic representation of the molecular structure</u>, which shows how atoms are arranged or spatially distributed. The chemical bonds within the molecule are shown, either explicitly or implicitly.
The cis / trans isomers are compounds that<u> differ in the spatial arrangement of their groups</u>. Particularly, the<u> cis isomers are geometric isomers that have the groups on the same side while the trans isomers are those that have them on opposite sides.
</u>
On the other hand, structural isomers are molecules with the<u> same molecular formula but different structure</u>.
The possible structural isomers of n-hexene that can be formed by moving the position of the double bond are shown in the picture attached, considering only the cis isomers.
The correct answer for this question is this one: "Yes, the protein retain its shape under these conditions. Assuming that you have isolated a protein from an organism in its proper shape, and you have treated it with an enzyme that selectively targets and breaks only the peptide bonds in the proteins." Hope this helps answer your question and have a nice day ahead.
The balanced equation for the burning of N-butane is;
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O
stoi. ratio 2 : 13 : 8 : 10
molar mass 58 32 44 18
moles X 13 X/2 8X/2 10X/2
105.86 688.10 423.45 529.31
produced mass 18632.8 g 9527.6 g
moles of n-butane = X = 6.14 x 10³ g / 58 g mol⁻¹
hence other moles of compounds can be calculated.
Mass = molar mass * moles
mass fraction = mass / total mass
hence the mass fraction of
CO₂ = 18632.8 / 6.14 x 10³ = 3.03
H₂O = 9527.6 / 6.14 x 10³ = 1.55
the required mass of air = 688.10 x 32 = 22019.2 g = 2.20 kg
Answer:
mass NH3 = 11.264 g
mass N2 = 9.264 g
Explanation:
balanced reaction:
∴ mass H2 = 2.00 g
∴ molar mass H2 = 2.016 g/mol
∴ molar mass N2 = 28.0134 g/mol
∴ molar mass NH3 = 17.031 g/mol
⇒ mol H2 = (2.00 g)*(mol/2.016 g) = 0.992 mol
⇒ mol NH3 = (0.992 mol H2)*(2 mol NH3/3 mol H2) = 0.6614 mol
⇒ mass NH3 = (0.6614 mol)*(17.031 g/mol) = 11.264 g
⇒ mol N2 = (0.6614 mol NH3)*(mol N2/2 mol NH3) = 0.3307 mol
⇒ mass N2 = (0.3307 mol)*(28.0134 g/mol) = 9.264 g
