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TEA [102]
3 years ago
14

Consider the lattice energy of any ionic compound. What combination of ions and charges will produce the largest (in magnitude)

lattice energies? a. small ions and small charges b. large ions and large charges c. small ions and large charges d. large ions and small charges
Chemistry
1 answer:
saul85 [17]3 years ago
3 0

Answer:

c. small ions and large charges

Explanation:

The lattice energy is a consequence of the electrostatic interaction between the ions. Coulomb force, is the force that drives this electrostatic interaction and is defined by the equation below:

F = \frac{Q1Q2}{r^{2} }

Q1 and Q2 are the charges of the ions and r is the distance between them. This means the the higher the charges and the smaller the distance (ionic radius), the stronger the force between ions and, therefore, the larger the lattice energy.

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In scientific notation, the number 0.00262 is expressed as
harkovskaia [24]

Answer:

2.62*10^-3

Explanation:

To do this by hand, you need to understand the rules of scientific notation.

5 0
3 years ago
Read 2 more answers
The area of the gold electrodes on the quartz crystal microbalance at the opening of Chapter 2 is 3.3 mm^2. One gold electrode i
aleksandrvk [35]

This question is incomplete, the complete question is;

The area of the gold electrodes on the quartz crystal microbalance at the opening of Chapter 2 is 3.3 mm^2. One gold electrode is covered with DNA at a surface density of 1.2 pmol/cm2.

(a) How much mass of the nucleotide cytosine (C) is bound to the surface of the electrode when each bound DNA is elongated by one unit of C. The mass formula mass of the bound nucleotide is cytosine + deoxyribose + phosphate = C9H10N3O6P = 287.2 g/mol

Answer: mass of the nucleotide (c) bound is 11.37 g

Explanation:

Given that the area of gold electrodes = 3.3 mm^2

surface density of one gold electrode = 1.2 pmol/cm^2

that is to that in every 1 cm^2 of area, 1.2 pmol DNA is present

therefore

mass of nucleotide present in 3.3 mm^2 is;

= (1.2/100 * 3.3) pmol

= 0.0396 pmol

we were given that formula mass of the bound nucleotide = 287.2 g/mol

so

mass of the nucleotide (c) bound = ( 287.2 * 0.0396 )g

mass of the nucleotide (c) bound =  11.37 g

5 0
3 years ago
According to the diagram below, a bacterial cell does not contain
Pavlova-9 [17]

Answer:

nucleus

Explanation:

3 0
3 years ago
Calculate freeze 62.9 g of iron at 1535oC<br> Hf (J/g)=257
Inessa [10]

Answer:

<u>-16200J</u>

Explanation:

(257J/g)(62.9g)

eliminate the variables

u get 16165.3

go to 3 significant digits

u get 16200

and since it is freezing we are taking out energy so it would be

-16200J

4 0
3 years ago
Can someone help me out with this please
Dmitriy789 [7]

Answer:

molar \: mass \: of \: copper(ii)nitrate = 64 + (14 + 48) \times 3 \\  = 250 \: g \\ 64 \: g \: of \: copper \: produces \: 250 \: g \: of \: copper \: nitrate \\ 10.36 \: g \: of \: copper \: will \: produce \: ( \frac{10.36 \times 250}{64} ) \: g \\  = 40.7 \: g

5 0
3 years ago
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