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Maksim231197 [3]
3 years ago
8

How fast should a girl of 35 kg run so that her kinetic energy becomes 700J of?

Physics
2 answers:
Kipish [7]3 years ago
6 0
V^2 = 700J/0.5*35kg

V = square root of 40

v = 6.324 m/s
Alenkinab [10]3 years ago
6 0

Answer:

√40m/sec

Explanation:

As we know Kinetic energy = 1/2 mv^2

700 = 1/2 x 35 x v^2

1400/35 = v^2

√40 = v

So v, √40m/sec

Hope this helps you.

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Answer :

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(b) The distance covered by the car is, 150 m

Explanation :  

By the 1st equation of motion,

v=u+at ...........(1)

where,

v = final velocity = 5 m/s

u = initial velocity  = 25 m/s

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a = acceleration  of the car = ?

Now put all the given values in the above equation 1, we get:

5m/s=25m/s+a\times (10s)

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By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2 ...........(2)

where,

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Now put all the given values in the above equation 2, we get:

s=(25m/s)\times (10s)+\frac{1}{2}\times (-2m/s^2)\times (10s)^2

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3 years ago
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Explanation:

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