How fast should a girl of 35 kg run so that her kinetic energy becomes 700J of?

Physics

2 answers:

Kipish [7]3 years ago

6 0

V^2 = 700J/0.5*35kg

V = square root of 40

v = 6.324 m/s

Alenkinab [10]3 years ago

6 0

Answer:

√40m/sec

Explanation:

As we know Kinetic energy = 1/2 mv^2

700 = 1/2 x 35 x v^2

1400/35 = v^2

√40 = v

So v, √40m/sec

Hope this helps you.

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