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Maksim231197 [3]
2 years ago
8

How fast should a girl of 35 kg run so that her kinetic energy becomes 700J of?

Physics
2 answers:
Kipish [7]2 years ago
6 0
V^2 = 700J/0.5*35kg

V = square root of 40

v = 6.324 m/s
Alenkinab [10]2 years ago
6 0

Answer:

√40m/sec

Explanation:

As we know Kinetic energy = 1/2 mv^2

700 = 1/2 x 35 x v^2

1400/35 = v^2

√40 = v

So v, √40m/sec

Hope this helps you.

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When a 25-kg crate is pushed across a frictionless horizontal floor with a force of 200 N, directed 20 below the horizontal, th
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Explanation:

Given that the force used to push the crate is F = 200N

The force directed 20° below the horizontal

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Weight of the crate can be determine using

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Check attachment. For free body diagram and better understanding

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N = 245 + 68.4

N = 313.4 N

The normal force is approximately 310 N to the nearest ten

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