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Reika [66]
3 years ago
8

20

Physics
1 answer:
Pani-rosa [81]3 years ago
4 0
The total displacement is 4.0 m east.
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How does an object's position and velocity change as the object accelerates
Morgarella [4.7K]
If an object<span> is slowing down, then its </span>acceleration<span> is in the opposite direction of its motion. ... In Example A, the </span>object<span> is moving in the positive direction (i.e., has a positive </span>velocity<span>) and is speeding up. When an </span>object<span> is speeding up, the </span>acceleration<span> is in the same direction as the </span>velocity<span>.</span>
4 0
4 years ago
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This is the sum of all the forces applied to an object. It is usually separated into a horizontal and vertical component.
evablogger [386]

Answer: Net Force, also is referred to as Resultant Force

5 0
3 years ago
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A piece of glass has a temperature of 72.0 degrees Celsius. The specific heat capacity of the glass is 840 J/kg/deg C. A liquid
Nezavi [6.7K]

Answer:

741 J/kg°C

Explanation:

Given that

Initial temperature of glass, T(g) = 72° C

Specific heat capacity of glass, c(g) = 840 J/kg°C

Temperature of liquid, T(l)= 40° C

Final temperature, T(2) = 57° C

Specific heat capacity of the liquid, c(l) = ?

Using the relation

Heat gained by the liquid = Heat lost by the glass

m(l).C(l).ΔT(l) = m(g).C(g).ΔT(g)

Since their mass are the same, then

C(l)ΔT(l) = C(g)ΔT(g)

C(l) = C(g)ΔT(g) / ΔT(l)

C(l) = 840 * (72 - 57) / (57 - 40)

C(l) = 12600 / 17

C(l) = 741 J/kg°C

5 0
4 years ago
_______ are atoms that carry an electric charge.
Tju [1.3M]
The answer is D. hope this helps.
5 0
3 years ago
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A magnetic field of magnitude 1.30x10-3 T is measured a distance of 0.03 m from a long straight wire. What is the current throug
Ivan

Answer:

I=195A

Explanation:

According to the Biot–Savart law, the magnitude of a magnetic field created by the current in a long straight wire, is defined as:

B=\frac{\mu_0I}{2\pi R}

Where \mu_0 is the permeability of free space, I is the current circulating on the wire and R is the distance from the point where B is measured.

Solving for I:

I=\frac{2\pi BR}{\mu_0}\\I=\frac{2\pi(1.3*10^{-3}T)(0.03m)}{4\pi*10^{-7}\frac{T\cdot m}{A}}\\I=195A

4 0
4 years ago
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