Answer:
Explanation:
The expression which represent the first diffraction minima by a circular aperture is given by --------eqn 1
The angle through which the first minima is diffracted is given by ---------eqn 2
As is very small so we can write
So from eqn 1 and eqn 2 we can write
--------eqn 3
Here is the position of first maxima D is the distance of screen from the circular aperture d is the diameter of aperture
It is given that diameter of circular aperture is 14.7 cm so
Now putting all these value in eqn 3
