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uranmaximum [27]
3 years ago
12

How many neutrons does element X have if its atomic number is 22 and its mass number is 96?

Physics
1 answer:
Dovator [93]3 years ago
6 0
1. The mass number is protons + neutrons = mass number. In this case, we have protons + neutron = 164.The atomic number is simply the number of protons so we have 43 + neutrons = 164. Subtracting 43 from both sides we get neutrons = 121.
2.  = 4

3. The number of protons in the nucleus does not equal the number of neutrons. 

A=mass number: 
Z=atomic number (= number of protons)
N=number of neutrons:

A=Z+N

If the number of protons in the nucleus is equal the number of neutrons , we would have an even mass number; because Z=N=x; then A=x+x=2x  (this is always an even number) but  23 is an odd number, therefore the number of protons in the nucleus does not equal the number of neutrons.
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When is the electric flux on a section of a closed surface positive?.
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When the electric field pierces outward through the section.
5 0
2 years ago
A turntable that spins at a constant 80.0 rpmrpm takes 3.50 ss to reach this angular speed after it is turned on. Find its angul
Veronika [31]

Answer:

The angular acceleration is <u>2.39 rad/s²</u>.

The number of degrees it rotates is <u>841.68 degrees</u>.

Explanation:

Given:

Initial angular speed (ω₀) = 0 rad/s

Final angular speed in rpm (N) = 80.0 rpm

Time taken (t) = 3.50 s

First, let us determine the final angular speed in radians per second.

We know that,

\omega=\frac{2\pi N}{60}\ rad/s

Plug in the values and find the final angular speed, 'ω'. This gives,

\omega=\frac{2\pi\times 80.0}{60}=8.38\ rad/s

Now, using equation of motion for rotational motion, we have:

\omega=\omega_0+\alpha t\\\\\alpha\to angular\ acceleration

Plug in the given values and solve for α. This gives,

8.38=0+\alpha \times 3.50\\\\\alpha=\frac{8.38}{3.50}=2.39\ rad/s^2

Therefore, the angular acceleration is 2.39 rad/s².

Now, again using rotational equation of motion relating angular displacement, we have:

\omega^2=\omega_0^2+2\alpha\theta\\\\\theta=\frac{\omega^2-\omega_0^2}{2\alpha }

Plug in the given values and solve for 'θ'. This gives,

\theta=\frac{(8.38)^2-0}{2\times 2.39}\\\\\theta=\frac{70.2244}{4.78}=14.69\ rad

Convert radians to degrees using the conversion factor. This gives,

π radians = 180°

So, 1 radian =( 180 ÷ π ) degrees

Therefore, 14.69\ rad=14.69\times (\frac{180}{\pi})=841.68^\circ

So, the number of degrees it rotates is 841.68 degrees.

3 0
3 years ago
A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete
NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}

From Rayleigh criteria

sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm

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3 0
3 years ago
1. A kangaroo hops 84 m to the east in 7 seconds.
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Explanation:

Given parameters:

Distance hopped  = 84m

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Unknown:

Speed of kangaroo  = ?

Velocity of kangaroo  = ?

Solution:

To solve this problem,

    Speed  = \frac{distance}{time }   = \frac{84}{7}  = 12m/s

  Velocity  = \frac{displacement}{time}   = \frac{84}{7}   = 12m/s due east

3 0
3 years ago
What happens In a nuclear fission reaction
irina1246 [14]
Look at the  third one i think its the answer 
3 0
3 years ago
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