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Sever21 [200]
3 years ago
8

For each of the following numbers, determine the number of significant figures it contains, rewrite it without using scientific

notation, and determine the number of significant figures in the result. (a) 3.050 x 10^-4, (b) 4.3200 x 10^2,(c) 8.001 x 10^-7, (d) 2.006080 x 10^5, (e) 1.503 x 10^-5, (f) 6.07510 x 10^4.
Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

Explanation:

a) .0003050                    significant figure - 4

b) 432.00                          significant figure-5

c) .0000008001                significant figure -4

d) 200608.0                       significant figure -7

e) .00001503                       significant figure-4

f) 60751.0                              significant figure- 6.

zero after decimal are all significant . zero before decimal is significant only when it is preceded by a digit.All digits are significant.

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Answer:

The density is 3g/L

Explanation:

The reaction that occurs in the vessel is:

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10,0g of NH₃ are:

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For a complete reaction of O₂ there are necessaries:

0,203 mol * \frac{4molNH_{3}}{5molO_{2}}= 0,163 moles of NH_{3}

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0,587 - 0,163 = <em>0,424 moles of NH₃</em>

These moles are:

0,424mol * \frac{17,031g}{1mol} = <em>7,22g of NH₃</em>

Knowing O₂ is limiting reactant, mass of NO and H₂O are:

0,203molO_{2}*\frac{4molNO}{5molO_{2}}*\frac{30,01g}{1molNO} = <em>4,87g of NO</em>

0,203molO_{2}*\frac{6molH_{2}O}{5molO_{2}}*\frac{18,02g}{1molH_{2}O} = <em>4,39g of H₂O</em>

The total mass is: 7,22g + 4,87g + 4,39g = 16,48g ≡ <em>16,5g </em>

<em>-</em><em>The same mass add in the first. By matter conservation law-</em>

As vessel volume is 5,50L, density is:

16,5g/5,50L = <em>3g/L</em>

I hope it helps!

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