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Sever21 [200]
3 years ago
8

For each of the following numbers, determine the number of significant figures it contains, rewrite it without using scientific

notation, and determine the number of significant figures in the result. (a) 3.050 x 10^-4, (b) 4.3200 x 10^2,(c) 8.001 x 10^-7, (d) 2.006080 x 10^5, (e) 1.503 x 10^-5, (f) 6.07510 x 10^4.
Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

Explanation:

a) .0003050                    significant figure - 4

b) 432.00                          significant figure-5

c) .0000008001                significant figure -4

d) 200608.0                       significant figure -7

e) .00001503                       significant figure-4

f) 60751.0                              significant figure- 6.

zero after decimal are all significant . zero before decimal is significant only when it is preceded by a digit.All digits are significant.

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Oxyacids contains at least one h+ and an oxyanion. the " sulfurous " oxyacid contains the oxyanion ________.
Ulleksa [173]
The correct answer is Oxyanion Nitrite. Oxyanion is referred to as an ion which contains one or more oxygen atoms that are bonded to another chemical element. It has a generic formula of <span>A. </span>x<span>O </span>z− <span>y, wherein A, stands for a chemical element, while O, stands for an Oxygen atom</span>
7 0
3 years ago
The mass of 2.50 moles of calcium fluoride is ____ grams
Vesna [10]

Answer:

195.187016

Explanation:

3 0
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If 2.03 g of oxygen react with carbon monoxide, how many grams of CO2 are formed?
mamaluj [8]

Answer:

The suitable equation for this reaction is

2CO + O₂ -----> 2CO₂

Here, we are given that we have 2 grams of O₂

From the equation, we can see that 2 * Moles of O₂ = Moles of CO₂

Moles of O₂:

2/32 = 1/16 moles

Therefore, the number of moles of CO₂ is twice the moles of O₂

Moles of CO₂ = 2 * 1/16

Moles of CO₂  formed = 1/8 moles

Mass of CO₂  formed = Molar mass of CO₂ * Moles of CO₂

Mass of CO₂  formed = 44 * 1/8

Mass of CO₂  formed = 5.5 grams

Hence, option B is correct

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8 0
3 years ago
The magnesium reacts with the hydrochloric acid to produce a gas and a salt.
jok3333 [9.3K]

Answe r H2

Explanation:

Mg +HCl=MgCl2 +H2

3 0
3 years ago
A 1.50 L buffer solution is 0.250 M in HF and 0.250 M in NaF. Calculate the pH of the solution after the addition of 0.100 moles
alexgriva [62]

Answer : The pH of the solution is, 3.41

Explanation :

First we have to calculate the moles of HF.

\text{Moles of HF}=\text{Concentration of HF}\times \text{Volume of solution}

\text{Moles of HF}=0.250M\times 1.50L=0.375mol

Now we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.8\times 10^{-4})

pK_a=4-\log (6.8)

pK_a=3.17

The reaction will be:

                             HF+OH^-\rightleftharpoons F^-+H_2O

Initial moles     0.375     0.100   0.375

At eqm.   (0.375-0.100)      0     (0.375+0.100)

                     = 0.275                    = 0.475

Now we have to calculate the pH of solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[F^-]}{[HF]}

Now put all the given values in this expression, we get:

pH=3.17+\log [\frac{(\frac{0.475}{1.50})}{(\frac{0.275}{1.50})}]

pH=3.41

Thus, the pH of the solution is, 3.41

8 0
3 years ago
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