As an object falls to the ground, its potential energy is being converted to kinetic energy.

Physics

1 answer:

alekssr [168]4 years ago

5 0

Answer:

The statement is true

Explanation:

Energy Conversion

When an object starts to fall in free air, it speeds up as it falls. The force of gravity acting on the object causes energy to be transferred from its gravitational potential energy to its kinetic energy. We can safely say the height converts to speed and vice-versa. If no external forces act on the system, we can easily calculate heights and speeds by knowing the total mechanical energy (gravitational potential plus kinetic) is conserved.

Answer:

$\boxed{\text{The statement is true}}$

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Help with physical science please

alex41 [277]

1. Elastic potential energy (D. EEl)

In this situation, the spring is compressed with the toy on top of it. The toy is stationary, so it does not have kinetic energy. However, the spring is compressed, so it does have elastic potential energy, given by:

$E_{EL}=\frac{1}{2}kx^2$

where k is the spring constant and x is the compression of the spring.

2. Gravitational potential energy (C. Eg)

In this situation, the spring has been released, so it returns to its natural position, so its elastic potential energy is zero. The toy is also stationary, since it is at its top position, where its velocity is zero, so its kinetic energy is also zero. However, the toy is now at a certain height h above the spring, so it has gravitational potential energy given by:

$E_g = mgh$

where m is the mass of the toy and g is the gravitational acceleration.

3. Gravitational potential and kinetic energy (A. Eg and EK)

In this situation, the toy is falling: so, it is moving with a certain speed v, so it has kinetic energy given by

$E_k = \frac{1}{2}mv^2$

Also, since it is at a certain height above the spring, it still has some gravitational potential energy, as in the previous point.

4. Gravitational potential energy (C. Eg)

The jumper is standing on the bridge, so it has gravitational potential energy given by its height h above the ground:

$E_g=mgh$

where m is the mass of the jumper.

5. This exercise has the same text of the previous one.

8 0

3 years ago

An airplane awaiting departure is cleared to takeoff, its accelerates down a runway at 3.20m/ s2 for 32.8s until it finally lift

stich3 [128]

The final velocity before takeoff is 104.96 m / s.

Explanation:

The last velocity of a given object over some time defines the final velocity. The final velocity of the object is given by the product of acceleration and time and adding this product to the initial velocity.

To calculate the final velocity,

V = u + at

where v represents the final velocity,

u represents the initial velocity,

a represents the acceleration

t represents the time taken.

$v = 0 + (3.20)\times( 32.8)$