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Snezhnost [94]
3 years ago
10

In the equation for the gravitational force between two objects, which quantity must be squared?

Physics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

d

Explanation:

The quantity that must be squared in the equation of gravitational force is distance d.

According to the universal gravitational law, the square of the distance between two objects is inversely proportional to the force of gravity.

  • Therefore, the quantity to be squared is d

The formula is given as:

  Fg  = \frac{G m_{1} m_{2} }{d^{2} }  

So d is the quantity that must be squared

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Luba_88 [7]
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4 years ago
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In the kitchen of your house you would like to run a 240 W blender, a 30 W phone charger, a 720 W toaster oven, and two 120 W li
meriva

Current pulled by these appliances is 10.25 A

Explanation:

  • Step 1: Find the total power used by these appliances.

Total power = 240 + 30 + 720 + (2 × 120) = 1230 W

  • Step 2: Given voltage is 120 V, find the current by using the formula Power = Voltage × Current

⇒ Current(I) = P/V = 1230/120 = 10.25 A

8 0
3 years ago
A block of mass 12.2 kg is sliding at an initial velocity of 6.65 m/s in the positive x-direction. The surface has a coefficient
valentina_108 [34]

Explanation:

Given that,

Mass of the block, m = 12.2 kg

Initial velocity of the block, u = 6.65 m/s

The coefficient of kinetic friction, \mu_k=0.253

(a)The force of kinetic friction is given by :

f=\mu_k mg

mg is the normal force

So,

f=0.253\times 12.2\times 9.8\\\\f=30.24\ N

(b) Net force acting on the block in the horizontal direction,

f = ma

a is the acceleration of the block

a=\dfrac{f}{m}\\\\a=\dfrac{30.24}{12.2}\\\\a=2.47\ m/s^2

(c) Let d is the distance covered by the block before coming to the rest. Using third equation of motion as follows :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(6.65)^2}{2\times 2.47}\\\\d=-8.95\ m

Hence, this is the required solution.

3 0
4 years ago
A baseball is thrown directly upward at time t= 0 and is caught again at time t=5s. Assume that air resistance is so small that
babymother [125]

Answer:

Explanation:

since the ball was thrown at 0s and caought again at 5 s. applying eqaution  of motion.

s = ut-\frac{1}{2}\times g \times t^{2}

0 = u×5 - \frac{1}{2}×10×5×5

solving the eqaution we gaet initial velocity u = 25 m/s.

there fore total energy E = \frac{1}{2}×m×25×25 J

where m is the mass of the ball according to conservation of energy E remains constant

conservation of energy:

kinetic + potential energy of the ball = E

kinetic energy = E - mgh                              \rightarrow    1

h = ut - \frac{1}{2}\times g\times t^{2}

applying ot in the eqaytion 1

kinetic energy = e - mg(25t - \frac{1}{2}\times g\times t^{2})         2

Therefore kinetic energy vs height will be a straight line with negative slope and kinetic energy vs time will be parabola that is open upward.

6 0
3 years ago
-1
Rom4ik [11]

Answer:

9800 N

Explanation:

applying,

W = Fd.................. Equation 1

Where W = work done by the engine, F = Force exterted to lift the beam, d = distance.

make F the subject of the equation

F = W/d............... Equation 2

From the question,

Given: W = 1421000 J, d = 145 meters.

Substitute these values into equation 2

F = 1421000/145

F = 9800 N

5 0
3 years ago
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