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34kurt
3 years ago
14

Which of the following is an example of a mechanical wave?

Physics
2 answers:
Elanso [62]3 years ago
5 0
D. The noise of a car horn. Hope this helps! Please comment if it does!
lions [1.4K]3 years ago
3 0

Answer:

d

Explanation:

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Slow-twitch muscles<span> help enable long-endurance feats such as distance running, while fast-</span>twitch muscles<span> fatigue faster but are used in powerful bursts of movements like sprinting. Hope that this can help!!!</span>
8 0
3 years ago
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A ball is thrown straight up in the air and just before it lands it is travelling -47.5 m/s. How long was the ball in the air?
Setler [38]
Use v = u + at
Message me if you need more help
6 0
3 years ago
A 12.0-g bullet is fired horizontally into a 109-g wooden block that is initially at rest on a frictionless horizontal surface a
kykrilka [37]

Answer:

v₀ = 280.6 m / s

Explanation:

we have the shock between the bullet and the block that we can work with at the moment and another part where the assembly (bullet + block) compresses a spring, which we can work with mechanical energy,

We write the mechanical energy when the shock has passed the bodies

   Em₀ = K = ½ (m + M) v²

We write the mechanical energy when the spring is in maximum compression

Em_{f} = K_{e} \\= \frac{1}{2} kx^2\\    Em_0 = Em_{f}

½ (m + M) v² = ½ k x²

Let's calculate the system speed

   v = √ [k x² / (m + M)]

   v = √[152 ×0.78² / (0.012 +0.109) ]

   v = 27.65 m / s

This is the speed of the bullet + Block system

Now let's use the moment to solve the shock

Before the crash

   p₀ = m v₀

After the crash

p_{f} = (m + M) v

The system is formed by the bullet and block assembly, so the forces during the crash are internal and the moment is preserved

 p_0 =  p_{f}

  m v₀ = (m + M) v

  v₀ = v (m + M) / m

let's calculate

v₀ = 27.83 (0.012 +0.109) /0.012

  v₀ = 280.6 m / s

4 0
2 years ago
An object is held at rest and allowed to drop How far does the object fall in 3.3 seconds?
IgorC [24]
After x seconds, an object will fall \frac{1}{2}at^2 where a is acceleration due to gravity and t is time

so when t=3.3
the distance it will fall is (\frac{1}{2})(9.8\frac{m}{s^2})(3.3m)^2=53.361m
it will fal 53.361 meters
6 0
3 years ago
3. What is the gravitational force between a 70 kg physics student and her 1 kg textbook, at a distance of 1 meter? (This number
Rina8888 [55]

ANSWER

\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}

EXPLANATION

Parameters given:

Mass of the student, M = 70 kg

Mass of the textbook, m = 1 kg

Distance, r = 1 m

To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:

F=\frac{GMm}{r^2}

where G = gravitational constant

Therefore, the gravitational force acting between the student and the textbook is:

\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\  \\ F=4.67*10^{-9}\text{ }N \end{gathered}

That is the answer.

6 0
1 year ago
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