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34kurt
3 years ago
14

Which of the following is an example of a mechanical wave?

Physics
2 answers:
Elanso [62]3 years ago
5 0
D. The noise of a car horn. Hope this helps! Please comment if it does!
lions [1.4K]3 years ago
3 0

Answer:

d

Explanation:

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A sound wave has a wavelength of 1.32 m and travels at a speed of
kati45 [8]

Answer:

0.00377143

Explanation:

You would have to divide to get the frequency.


1.32/350 = 0.00377143

I apologize if it is incorrect-

I hope it helps! Have a great day!

Anygays-

6 0
2 years ago
Which one of the following is not a step in the inquiry process
posledela
Classify is not a step in the inquiry process
7 0
3 years ago
Read 2 more answers
Water flowing through a cylindrical pipe suddenly comes to a section of pipe where the diameter decreases to 86% of its previous
Orlov [11]

Answer:

Explanation:

The speed of the water in the large section of the pipe is not stated

so i will assume 36m/s

(if its not the said speed, input the figure of your speed and you get it right)

Continuity equation is applicable for ideal, incompressible liquids

Q the flux of water that is  Av with A the cross section area and v the velocity,

so,

A_1V_1=A_2V_2

A_{1}=\frac{\pi}{4}d_{1}^{2} \\\\ A_{2}=\frac{\pi}{4}d_{2}^{2}

the diameter decreases 86% so

d_2 = 0.86d_1

v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}\\\\=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\\\\\approx1.35v_{1} \\\\v_{2}\approx(1.35)(38)\\\\\approx48.6\,\frac{m}{s}

Thus, speed in smaller section is 48.6 m/s

3 0
3 years ago
What is the chemical name of SiF4? sulfur fluoride silicon fluoride sulfur tetrafluoride silicon tetrafluoride
baherus [9]

Answer:

Silicon tetrafluoride

Explanation:

The symbol Si represents the element silicon, as shown in the periodic table.

The are 4 fluorines, so the prefix for fluoride must have tetra-

8 0
3 years ago
Owen throws a baseball straight upward. We can ignore air resistance.
dusya [7]

Answer:

The acceleration of the ball is constant and equal to -9.81 m/s² (acting downwards)

The velocity of the ball reduces at a constant rate with time on its way up

Explanation:

The motion of the ball upwards is described by the following equation;

v = u - g × t

v² = u² - 2 × g × s

Where;

v = The final velocity of the ball

u = The initial velocity of the ball

g = The acceleration due to gravity = Constant

s = The height of the bass after a given time, t

t = The time in which the ball is rising

Therefore, the acceleration of the ball = The acceleration due to gravity  (Constant) = -9.81 m/s²↓

From v = u - g × t = u - 9.81 × t , the velocity of the ball reduces at a constant rate with time on its way up.

7 0
3 years ago
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