The chemical symbol always begins with a capital letter.
.
Answer:
a) 23.2 e V
b) energy of the original photon is 36.8 eV
Explanation:
given,
energy at ground level = -13.6 e V
energy at first exited state = - 3.4 e V
A photon of energy ionized from ground state and electron of energy K is released.
h ν₁ - 13.6 = K
K combine with photon in first exited state giving out photon of energy
= 26.6 e V
h c = 6.626 × 10⁻³⁴ × 3 × 10⁸ = 12400 e V A°
K + ( 3.4 ) = 26.6 e V
a) energy of free electron
K = 26.6 - 3.4 = 23.2 e V
b) energy of the original photon
h ν₁ - 13.6 = K
h ν₁ = 23.2 + 13.6
= 36.8 e V
energy of the original photon is 36.8 eV
I would say D.) The ball bounces many times suggesting the energy is used up efficiently
Answer:
0.0319 m³
Explanation:
Use ideal gas law:
PV = nRT
where P is pressure, V is volume, n is amount of gas, R is the gas constant, and T is temperature.
Since P, n, and R are held constant:
n₁ R / P₁ = n₂ R₂ / P₂
Which means:
V₁ / T₁ = V₂ / T₂
Plugging in:
0.0279 m³ / 280 K = V / 320 K
V = 0.0319 m³
Answer:
The frequency of wave is 160Hz.
Explanation:
Given that the formula of speed is V = f×λ where V represents speed, f is frequency and λ is wavelength.
So first thing, you have to make frequency the subject by dividing wavelength on both sides :



Next you have to substitute the value of v and f into the formula :
Let λ = 2.5m,
Let v = 400m/s,

