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3 years ago

10

The movement of crustal plates is best described as a:

2 answers:

JulijaS [17]3 years ago

5 0

Я в России не будет так классно было в прошлом и настоящем человеке и в России в г щеки как у щ есть и в этом случае не знаю что это не так как в России не ебыло щит и не кзнаю в контакте г не знаю почему так мало ее и не только в России не будет в России не щ и не только в щтом г

bazaltina [42]3 years ago

5 0

Answer:

it is number 3, continuing long-term process

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A sound source producing 1.00 kHz waves moves toward a stationary listener at one-half the speed of sound.

SIZIF [17.4K]

Answer:

2000Hz and 1500Hz

Explanation:

Using

a) f = f0((c+vr)/(c+vs))

=>>> f0((c)/(c-0.5c))

=>>>1000/0.5 = 2000Hz

b) f = f0((c+vr)/(c+vs))

=>>>f0((c+0.5c)/(c))

=>>>>1000 x 1.5 = 1500Hz

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3 years ago

Which part of this model represents a layer made of liquid rock that produces

goblinko [34]

Answer: C- the outer core

Explanation: The outer core is a thick layer of molten rock that encircles the inner core.

7 0

3 years ago

Weight of a person's muscles, bones, tendons, and ligaments.

kenny6666 [7]

I’m pretty sure it’s lean mass but let another guy answer you before you use mine

6 0

3 years ago

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What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?

IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as $m_{1} \ and\ m_{2}\ respectively$

$Let\ m_{1} =1 kg\ and\ m_{2} =2 kg$

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

$m_{1} g-T=m_{1} a$ [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction $[\mu]=0.13$

$Hence\ the\ frictional\ force\ F=\mu N$

$F=\mu m_{2} g$

Hence the net force acting on the body having mass 2 kg-

$T-\mu m_{2} g=m_{2} a$ [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

$m_{1} g-T=m_{1}a$ [1]

$T-\mu m_{2}g= m_{2} a$ [2]

---------------------------------------------------

$[m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a$

$a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g$

$a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2$

$a=\frac{0.74}{3} *9.8\ m/s^2$

$a=2.417 m/s$ [ans]

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3 years ago

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At which temperature does the motion of atoms and molecules stop?

Aleks [24]

Absolute Zero, hopefully that helps :)

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3 years ago

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