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BARSIC [14]
3 years ago
11

How do solute concentrations affect the rate of osmosis within the cell?

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:

Image result for How do solute concentrations affect the rate of osmosis within the cell?

Concentration gradient - The movement of osmosis is affected by the concentration gradient; the lower the concentration of the solute within a solvent, the faster osmosis will occur in that solvent.

I think this is it^^^

Explanation:

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My atomic number is 35.453.
ruslelena [56]
CL 
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5 0
3 years ago
When Wolverine’s 10-pound adamantium claws are dissolved in 100 mL of 10 M nitric acid, 10.7 grams of adamantium nitrate are rec
Mazyrski [523]

The percent yield is 71.3 %.

Explanation:

Percent yield is the measure to analyze the success percentage of any experiment .The percent yield of any experiment can be obtained by the ratio of actual or experimental value to expected or theoretical value multiplied with 100.

Percent Yield = \frac{Experimental Outcome}{Theoretical Outcome} *100

So, in the present problem, we have obtained 10.7 g of adamantium nitrate from Wolverine's 10 pound claws. So the actual value or the experimental value is the amount of adamantium nitrate obtained from Wolverine's claws.

Thus, the experimental outcome is 10.7 g. While we had expected to recover 15 g of adamantium nitrate. So the theoretical outcome is 15 g.

Percent yield = \frac{10.7}{15} * 100 = 71.3 %

Thus, the percent yield is 71.3 %.

7 0
3 years ago
Given the balanced equation representing a reaction:
Nesterboy [21]

Answer:

It accepted a proton from HCl

Explanation:

When properly written, the equation box the reaction is given as; HCl(aq) + H2O(l) ----> H3O+(aq) + Cl-(aq).

According to Brownstead-Lowry definition of acids and bases, an acid donates protons while a base accepts protons.

Water molecule acts as a base in the reaction because it accepted a proton from HCl in the reaction above.

7 0
3 years ago
3. How much energy is needed to raise 45 grams of water from 40°C to 115 °C?
Dafna1 [17]

Answer:

Q = 114349.5 J

Explanation:

Hello there!

In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:

Q_1=45g*4.18\frac{J}{g\°C}*(100\°C-40\°C)=11286J\\\\Q_2=45g* 2260 \frac{J}{g} =101700J\\\\Q_3=45*2.02\frac{J}{g\°C}*(115\°C-100\°C)=1363.5J

Thus, the total energy turns out to be:

Q_T=11286J+101700J+1363.5J\\\\Q_T=114349.5J

Best regards!

5 0
3 years ago
The amount of a harmful chemical to which a person is exposed is the ____.
kotykmax [81]
A. dose
a dose is an amount, a response is an action, and pollutant and toxins are substances
6 0
3 years ago
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