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BARSIC [14]
3 years ago
11

How do solute concentrations affect the rate of osmosis within the cell?

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:

Image result for How do solute concentrations affect the rate of osmosis within the cell?

Concentration gradient - The movement of osmosis is affected by the concentration gradient; the lower the concentration of the solute within a solvent, the faster osmosis will occur in that solvent.

I think this is it^^^

Explanation:

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The mass of a block is 12 g and the volume is 6 ml. Calculate the density of the block.
HACTEHA [7]

Answer:

According to mass and volume,  block density is 2 g/ml

Explanation:

Density is a measure, usually used in physics and chemistry, that relates the mass and volume of a solid or compound.

In general terms, the density is directly proportional to the mass, and inversely proportional to the volume, so increasing the mass will also increase the density.

The formula used to calculate the density is

ρ = \frac{m}{V}

Therefore, according to the mass and density of the block

ρ = \frac{12}{6} = 2g/ml

Being the density of the block equal to 2 g/ml.

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100 PNTS ANSWER ASAP PLZ The density of a particular small rubber ball is 1.1 g/cm3. It was dropped into a 100 mL beaker filled
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Explanation:

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El aguacate al oxidarse, ¿que fenómeno es?, ¿físico, químico o alotropicos?​
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2 years ago
Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
galben [10]

The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

PV = nRT

1.5 × 12 = n × 0.0821 × 280

18 = n × 22.988

Divide both side by 22.988

n = 18 / 22.988

n = 0.783 mole

Next, we shall determine the mole of NaCl needed for the reaction.

F₂ + 2NaCl —> Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.

Finally, we shall determine the mass of 1.566 moles of NaCl.

  • Mole = 1.566 moles
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

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2 years ago
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