The balanced equation for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃<span>OH(g)
Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as
k = [</span>CH₃OH(g)] / [CO(g)] [H₂(g) ]²
By substitution,
k = 0.030 M / 0.020 M x (<span>0.072 M</span>)²
k = 289.35 M⁻²
Decomposition is a chemical reaction that breaks the reactant into two or more products. Moles of nitrogen gas
in the cylinder is 1.63 moles.
<h3>What is the ideal gas equation?</h3>
The ideal gas equation states the relation of the hypothetical ideal gas according to the pressure, volume, temperature and moles of the gas. It is given by,

Where,
Pressure (P) = 2000 kPa
Volume (V) = 2L
Temperature (T) = 295 K
Gas constant (R)= 0.08206
Substituting values in the equation:

Therefore, 1.63 moles are produced.
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brainly.com/question/26720901
Answer:
The net ionic equation is
C6H5COOH+ CN-= C6H5COO- + HCN
Explanation:
From the ionic equation
C6H5COOH + Na+ + CN- = C6H5COO- + Na+ + HCN
Only sodium is the spectator ion, so it cancels out, since C6H5COOH and HCN do not ionize completely they are left undissociated
<u>Answer:</u> Increasing temperature
<u>Explanation:</u>
The Principle of Le Chatelier states that <u>if a system in equilibrium is subjected to a change of conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.
</u>
The variation of one or several of the following factors can alter the equilibrium condition in a chemical reaction:
- Temperature
- The pressure
- The volume
- The concentration of reactants or products
In the case of the reaction in the question, <u>the change that moves the balance to the left will be the one that moves it towards the reagents</u>, that is, that favors the production of reagents instead of products.
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Decreasing the concentration of SO3 and increasing the concentration of SO2 <u>will favor the production of SO3</u>, which is the product of the reaction.
- Decreasing the volume increases the pressure of the system and the balance will move to where there is less number of moles. In the case of the reaction in question, we have 3 moles of molecules in the reactants (1 mole of O2 + 2 moles of SO2) while in the products there are 2 moles of SO3 only, therefore, <u>decreasing the volume will displace the balance to the right</u>, which corresponds to the sense in which there is less number of moles.
The reaction of the question is an exothermic since ΔH <0, therefore in the reaction heat is produced and it can be written in the following way,
2SO2(g) + O2(g) ⇌ 2SO3(g) + heat
- So, if we increase the temperature we will be adding heat to the system, so the balance would move to the left to compensate for the excess heat in the system.