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3 years ago

What do significant figures in a measurement include___________________________________.

Physics

1 answer:

yuradex [85]3 years ago

4 0

The significant figures in a measurement include:

All digits measured exactly,

One estimated digit.

<span>Significant figures can help us show the preciseness of a number.</span>

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A feather of mass 0.001 kg falls from a height of 2 m. Under realistic conditions, it experiences air resistance. Based on what

snow_tiger [21]

As per initial given conditions first we will find the initial potential energy of the feather

$U = mgh$

$m = 0.001 kg$

$g = 9.8 m/s^2$

$h = 2m$

$U = (0.001kg)(9.8 m/s^2)(2m)$

$U = 0.0196 J$

now we know that few amount of its initial energy is lost in form of frictional energy loss

so remaining energy will be less than the initial potential energy

So final answer would be

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3 years ago

a quantity of water is poured into a graduated cylinder, which reads 139 mL. what is the mass of the water in kilograms?

alexgriva [62]

The mass of water is 0.139 kg

Explanation:

The density of a substance is given by the equation

$\rho = \frac{m}{V}$

where

$\rho$ is the density

m is the mass of the substance

V is its volume

In this problem we have:

V = 139 mL is the volume of water

The density of water is:

$\rho = 1 g/mL$

Solving the equation for m, we find its mass:

$m=\rho V = (1.0)(139)=139 g$

And converting into kilograms,

$m=139 g = 0.139 kg$

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3 years ago

How does the collision challenge okonkwo's sense of identity?

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<span>Okonkwoâ€™s identity was challenged by the cultural collision because he feels like his culture is responsible for all o his problems. He feels like his culture represents him though. Since he is a leader, he has to obey his culture even though he feels that it is the cause of his problems. Later on, he realizes that he has become a relic and can no longer function.</span>

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3 years ago

On Earth, the gravitational Field strength is much than on the moon. If a piece of rock was taken from the Moon to the Earth, st

nikklg [1K]

Ok so I’m pretty sure the answer would be 2 because the mass of the rock would have the same mass on Earth as it has on the moon. Also the Density of a solid object remains constant meaning it doesn’t change. But the weight would change because the Earths gravitational pull is more than that of the moon. I hope this helped!

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3 years ago

Q C Ganymede is the largest of Jupiter's moons. Consider a rocket on the surface of Ganymede, at the point farthest from the pla

guapka [62]

The answer is $v=15.6 \mathrm{~km} / \mathrm{s}$ .

<h3>What is kinetic energy?</h3>

A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
Kinetic energy comes in five forms: radiant, thermal, acoustic, electrical, and mechanical.
The energy of a body in motion, or kinetic energy (KE), is essentially the energy of all moving objects. Along with potential energy, which is the stored energy present in objects at rest, it is one of the two primary types of energy.
Explain that a moving object's mass and speed are two factors that impact the amount of kinetic energy it will possess.

Determine the escape speed for the rocket from the planet-satellite system:

The potential energy of the rocket due to Ganymede when it is on the surface of the Ganymede is,

$U_1=-\frac{G M_{\mathrm{G}} m}{R_G}$

The potential energy of the rocket due to Jupiter

when it is on the surface of the Ganymede is,

$U_2=-\frac{G M_{\mathrm{J}} m}{R}$

Here, R is a separation between Jupiter and Ganymede.

To escape from the surface of Ganymede potential energy of the rocket due to Jupiter and Ganymede is equal to the kinetic energy of the rocket.

$\begin{aligned}&\frac{1}{2} m v^2+U_1+U_2=0 \\&\frac{1}{2} m v^2=-U_1-U_2 \\&\frac{1}{2} m v^2=\frac{G M_{\mathrm{G}} m}{R_G}+\frac{G M_{\mathrm{J}} m}{R} \\&\frac{1}{2} v^2=\frac{G M_{\mathrm{G}}}{R_G}+\frac{G M_{\mathrm{J}}}{R}\end{aligned}$

$v^2=\frac{2 G M_{\mathrm{G}}}{R_G}+\frac{2 G M_{\mathrm{T}}}{R}$

$v=\sqrt{2 G\left(\frac{M_{\mathrm{G}}}{R_G}+\frac{M}{R}\right)}$

$v=\sqrt{2\left(6.67 \times 10^{-11} \mathrm{~N} \cdot \mathrm{m}^2 / \mathrm{kg}^2\right)\left(\frac{1.495 \times 10^{23} \mathrm{~kg}}{2.64 \times 10^6 \mathrm{~m}}+\frac{1.90 \times 10^{27} \mathrm{~kg}}{1.071 \times 10^9 \mathrm{~m}}\right)}$

$v=15.6 \times 10^3 \mathrm{~m} / \mathrm{s}$

$v=15.6 \mathrm{~km} / \mathrm{s}$

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2 years ago