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2 years ago

After four half-lives of decay, what is the ratio of radioactive parent isotope to stable daughter isotope?

Physics

1 answer:

Margarita [4]2 years ago

3 0

Answer:

Ratio of parent to daughter nuclei is 16 : 1

1 : 0.0625

Explanation:

The half of a radioisotope is the time it will take half of the original mass to decay.

Let the original mass be y

After the first half life, the new mass will be y/2

After the second half decay, the new mass will be y/4

After the third half decay, the new mass will be y/8

After the fourth half life decay, the new mass will be y/16.

Thus the ratio of the mother nucleus to the daughter nucleus will be y : y/16

Multiply the ratio through by 16

= 16y : y

= 16 : 1

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Three identical 6.0-kg cubes are placed on a horizontal frictionless surface in contact with one another. The cubes are lined up

Westkost [7]

Answer:

24 N

Explanation:

$m$ = mass of the cube = $6.0 kg$

Consider the three cubes together as one.

$M$ = mass of the three cubes together = $3 m = 3 (6.0) = 18 kg$

$a$ = acceleration of the combination = 2 ms⁻²

$F$ = Force applied on the combination

Using Newton's second law

$F = ma = (18) (2) = 36 N$

$F_{L}$ = Force by the left cube on the middle cube

Consider the forces acting on left cube, from the force diagram, we have

$F - F_{L} = ma \\36 - F_{L} = (6) (2)\\F_{L} = 24 N$

4 0

2 years ago

Define limitations in the operation conditions of a pn junction<br>

suter [353]

Answer:

Such limitations are given below.

Explanation:

Each pn junction provides limited measurements of maximum forwarding current, highest possible inversion voltage as well as the maximum output level.
If controlled within certain adsorption conditions, the pn junction could very well offer satisfying performance.
In connector operation, the maximum inversion voltage seems to be of significant importance.

6 0

3 years ago

A straight, cylindrical wire lying along the x axis has a length L and a diameter d . It is made of a material described by Ohm'

Zepler [3.9K]

The magnitude and direction of the electric field in the wire are mathematically given as

$L &=[(v / L) v / m] \hat{i}$

<h3>What is the magnitude and direction of the electric field in the wire?</h3>

Generally, the equation for is mathematically given as

A cylindrical wire that is straight and parallel to the x-axis has the following dimensions: length L, diameter d, resistivity p, diameter d, potential v, and z length. combining elements from both sides

E d $x=\int d v.$

$\begin{aligned}&-E \int_0^L d x=\int_v^0 d v \\\therefore E \cdot L &=v \\L &=[(v / L) v / m] \hat{i}\end{aligned}$

In conclusion, the magnitude and direction of the electric field in the wire are given as

$L &=[(v / L) v / m]$