Answer:
The rope must have a force of 10084,21 N
Explanation
Acceleration calculation
The car acceleration is equal to the acceleration of the truck
ac: car acceleration![\frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
at: truck acceleration
)
equation(1)
Known information:
vi = Initial speed = 0, ti = initial time = 0
vf = Final speed = 13
, t = final time =5 s
We replaced the known information in the equation(1):
![ac = at = \frac{13-0}{15-0}](https://tex.z-dn.net/?f=ac%20%3D%20at%20%3D%20%5Cfrac%7B13-0%7D%7B15-0%7D%20)
![ac=ac=\frac{13}{15} \frac{m}{s}](https://tex.z-dn.net/?f=ac%3Dac%3D%5Cfrac%7B13%7D%7B15%7D%20%20%5Cfrac%7Bm%7D%7Bs%7D)
Dynamic analysis
The forces acting on the car are the following:
Wc: Car weight
N: normal force, road force on the car
Ff: Friction force
T: Force of tension
Car weight calculation:
![Wc=mc*g](https://tex.z-dn.net/?f=Wc%3Dmc%2Ag)
mc = Car mass = 2230kg
g = Gravity acceleration=9.8 ![\frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
![Wc= 2230*9.8](https://tex.z-dn.net/?f=Wc%3D%202230%2A9.8)
![Wc=21854 N](https://tex.z-dn.net/?f=Wc%3D21854%20N)
Normal force calculation:
Newton's first law
![sum Fy= 0](https://tex.z-dn.net/?f=sum%20Fy%3D%200)
![N-W=0](https://tex.z-dn.net/?f=N-W%3D0)
![N=W](https://tex.z-dn.net/?f=N%3DW)
![N=21854 N](https://tex.z-dn.net/?f=N%3D21854%20N)
Friction force calculation (Ff):
We have the formula to calculate the friction force:
Ff = μk * N Equation (3)
μk kinetic coefficient of friction
We know that μk = 0.373and N= 21854N ,then:
![Ff=0.373*21854](https://tex.z-dn.net/?f=Ff%3D0.373%2A21854)
![Ff=8151.54 N](https://tex.z-dn.net/?f=Ff%3D8151.54%20N)
Calculation of the tension force in the rope (T):
Newton's Second law
![sum Fx= mc*ac](https://tex.z-dn.net/?f=%20sum%20Fx%3D%20mc%2Aac)
![T-Ff=mc*ac](https://tex.z-dn.net/?f=T-Ff%3Dmc%2Aac)
![T=2230(\frac{13}{15}) + 8151.54](https://tex.z-dn.net/?f=T%3D2230%28%5Cfrac%7B13%7D%7B15%7D%29%20%2B%208151.54)
T=10084,21 N
Answer: The rope must have a force of 10084,21 N