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Furkat [3]
3 years ago
6

After four half-lives of decay, what is the ratio of radioactive parent isotope to stable daughter isotope?

Physics
1 answer:
Margarita [4]3 years ago
3 0

Answer:

Ratio of parent to daughter nuclei is 16 : 1

OR

1 : 0.0625

Explanation:

The half of a radioisotope is the time it will take half of the original mass to decay.

Let the original mass be y

After the first half life, the new mass will be y/2

After the second half decay, the new mass will be y/4

After the third half decay, the new mass will be y/8

After the fourth half life decay, the new mass will be y/16.

Thus the ratio of the mother nucleus to the daughter nucleus will be y : y/16

Multiply the ratio through by 16

= 16y : y

= 16 : 1

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Salsk061 [2.6K]

Answer: 12,600,000Cm

Explanation:

From the data's;

Charges(q) = 1.8 PC equal to 1.8 x 10^¹²C

Distance = 7 micrometer, is equal to 0.0000070m

From the equation of electric dipole moment, p= q x d, where q= charge, d=distance and p is the dipole moment.

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3 years ago
Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it
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<u>Answer:</u>

2N/cm

<u>Step-by-step explanation:</u>

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Who conducted the study?

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One good question to ask the toothpaste making company is who conducted the study?

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Objective reporting brainly.com/question/2242789

#learnwithBrainly

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