Question

Number pattern Write a recursive method called print Pattern() to output the following number pattern. Given a positive integer as input (Ex: 12), subtract another positive integer (Ex: 3) continually until 0 or a negative value is reached, and then continually add the second integer until the first integer is again reached.

Answer 1

Answer:

import java.util.Scanner;

public class NumberPattern {  

public static void printDec(int num1 , int num2)

{

   if(num1<0)

    return ;

   System.out.print(num1+" ");

   printDec(num1-num2,num2);

}

public static void printInc(int num1, int num2)

{

int curr = num1 - ((num1/num2)*num2);

curr = curr+num2;

printstart(num1,num2,curr);

}

public static void printstart(int num1 , int num2 , int curr)

{

    if(curr>num1)

     return;

    System.out.print(curr+" ");

    printstart(num1,num2,curr+num2);

}

public static void printNumPattern(int num1 , int num2)

{

  printDec(num1,num2);

  printInc(num1,num2);

}

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

printNumPattern(num1, num2);

}

}

Explanation:

Answer 2

Answer:

See explaination

Explanation:

Code;

import java.util.Scanner;

public class NumberPattern {

public static int x, count;

public static void printNumPattern(int num1, int num2) {

if (num1 > 0 && x == 0) {

System.out.print(num1 + " ");

count++;

printNumPattern(num1 - num2, num2);

} else {

x = 1;

if (count >= 0) {

System.out.print(num1 + " ");

count--;

if (count < 0) {

System.exit(0);

}

printNumPattern(num1 + num2, num2);

}

}

}

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

printNumPattern(num1, num2);

}

}

See attachment for sample output