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Helen [10]
3 years ago
13

Solve the literal equation for y; cy+3=6d-2y

Mathematics
2 answers:
victus00 [196]3 years ago
7 0
<span>cy+3=6d-2y
cy + 2y = 6d - 3
(c + 2)y = 6d - 3
y = (6d - 3)/(c + 2)</span>
densk [106]3 years ago
3 0
I will do my best to explain what is done, but feel free to ask if you have questions on what I did:
cy+3=6d-2y
bring all the "y"s to one side
cy+3-3=6d-2y-3
cy+2y=6d-3-2y+2y
this should be your result...
cy+2y=6d-3
now divide y out to isolate it:
y(c+2)=6d-3
then divide our c+2 so your y is alone
\frac{y(c+2)}{c+2}= \frac{6d-3}{c+2}
you should get this as your answer:
y= \frac{6d-3}{c+2}

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Step-by-step explanation:

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\frac{b}{7a^2c}

Express the denominator as 35a^3c^3

To do this, we divide35a^3c^3 by the denominator

\frac{35a^3c^3}{7a^2c} = 5ac^2

So, the required fraction is:

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\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}

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Hence:

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