Question

Solve the literal equation for y; cy+3=6d-2y

Answer 1

cy+3=6d-2y
cy + 2y = 6d - 3
(c + 2)y = 6d - 3
y = (6d - 3)/(c + 2)

Answer 2

I will do my best to explain what is done, but feel free to ask if you have questions on what I did:
$cy+3=6d-2y$
bring all the "y"s to one side
$cy+3-3=6d-2y-3$
$cy+2y=6d-3-2y+2y$
this should be your result...
$cy+2y=6d-3$
now divide y out to isolate it:
$y(c+2)=6d-3$
then divide our c+2 so your y is alone
$\frac{y(c+2)}{c+2}= \frac{6d-3}{c+2}$
you should get this as your answer:
$y= \frac{6d-3}{c+2}$