Solve the literal equation for y; cy+3=6d-2y

Mathematics

2 answers:

victus00 [196]3 years ago

7 0

densk [106]3 years ago

3 0

I will do my best to explain what is done, but feel free to ask if you have questions on what I did:
$cy+3=6d-2y$
bring all the "y"s to one side
$cy+3-3=6d-2y-3$
$cy+2y=6d-3-2y+2y$
this should be your result...
$cy+2y=6d-3$
now divide y out to isolate it:
$y(c+2)=6d-3$
then divide our c+2 so your y is alone
$\frac{y(c+2)}{c+2}= \frac{6d-3}{c+2}$
you should get this as your answer:
$y= \frac{6d-3}{c+2}$

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Read 2 more answers

<img src="https://tex.z-dn.net/?f=%284%20%2B%206i%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(4 + 6i) {}^{2} " alt="(4 +

34kurt

Answer:

$36i^{2}+48i+16$

Step-by-step explanation:

$(4+6i)^{2}$ is essentially $(4+6i)(4+6i)$ (you are squaring $(4+6i)$ , so multiplying it by itself), so to simplify, you would need to distribute.

A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.

$(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$