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3 years ago

Which one of these is an element carbon carbon dioxide air water

1 answer:

8 0

Carbon is an element.
Carbon dioxide is a compound
air is a mixture
water can be both a compound/mixture depending on the type

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What would diluting the vinegar do to the rate of a reaction between vinegar and sodium hydroxide? decrease the rate of reaction

GarryVolchara [31]

Vinegar is aceti acid diluted in water.

The reaction of vinegar with sodium hydroxide is:

CH3COOH + NaOH ---> CH3COONa + H2O

That is an acid-base reaction.

The speed of reaction is proportional to the concentrations of the reactants.

Then, given thatn when you dilute the vinegar you decrease the concentration of CH3COOH, the rate of reaction will decrease.

Answer: decrease the rate of reaction.

4 0

2 years ago

2 C2H6 + 7 026 H2O + 4 CO2

Kay [80]

Answer:

Oxygen is limiting reactant

Explanation:

Based on the chemical reaction:

2C2H6 + 7O2 → 6H2O + 4CO2

<em>2 mole of ethane reacts with 7 moles of oxygen</em>

<em />

For a complete reaction of 5.25 moles of ethane are required:

5.25 moles Ethane * (7mol Oxygen / 2mol Ethane) = 18.38 moles of oxygen

As there are just 15.0 moles of oxygen

<h3>Oxygen is limiting reactant</h3>

3 0

2 years ago

What is the right answer for this. I really need help

statuscvo [17]

<span>así que te está diciendo que</span>

6 0

3 years ago

Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a

slega [8]

Answer:

$\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

$\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}$

From Equation (2), the molar ratio of iodine to thiosulfate is

$\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}$

Combining the two ratios, we get

$\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}$

7 0

3 years ago

The stored energy in a battery can BEST be described as:

34kurt

Chemical is the answer your looking for.

3 0

3 years ago

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