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guapka [62]
3 years ago
13

the metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off. the s

imple process in which kind of a change
Physics
1 answer:
Travka [436]3 years ago
3 0
When the metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off, this is an example of resistance, which provides light and heat. 
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If you know that the universe is estimated to be 14 billion years old . what is the age of the universe in seconds ???? (knowing
Svetlanka [38]

Answer:

<em>The estimated age of the universe is</em> 4.42*10^{17}\ seconds

Explanation:

<u>Time Units Conversion</u>

Sometimes we need to express magnitudes in different units, depending on the specific situation handled in the question or problem at hand. Magnitudes like length, time, mass, temperature, pressure, etc., can be expressed in several different units.

The most common units for time are years, months, days, hours, minutes, and seconds. There are 3,600 seconds in one hour and 24 hours in one day.

We are given the estimated age of the universe as 14 billion solar years. If one solar year is 365.25 days long, then the age, expressed in days is

14,000,000,000 * 365.25 days

Some quantities need to be expressed in scientific notation. This is the case since the numbers are too high

14,000,000,000 * 365.25 = 5.1135*10^{12}\ days

There are 24*3600=86400 seconds in one day, so

5.1135*10^{12}\ days=5.1135*10^{12} * 86400 =4.42*10^{17}\ seconds

The estimated age of the universe is 4.42*10^{17}\ seconds

6 0
3 years ago
Read 2 more answers
g You shine orange laser light that has a wavelength of 600 nm through a narrow slit. The slit forms a diffraction pattern on a
zimovet [89]

Answer:

 λ = 3 10⁻⁷ m,   UV laser

Explanation:

The diffraction phenomenon is described by the expression

         a sin θ = m λ

let's use trigonometry

         tan θ = y / L

as in this phenomenon the angles are small

        tan θ = \frac{sin \ \theta}{cos \ \theta} = sin θ

        sin θ = y / L

we substitute

      a y / L = m  λ

let's apply this equation to the initial data

       a  0.04 / L = 1 600 10⁻⁹

       a / L = 1.5 10⁻⁵

now they tell us that we change the laser and we have y = 0.04 m for m = 2

      a 0.04 / L = 2  λ

       a / L = 50  λ

we solve the two expression is

         1.5 10⁻⁵ = 50  λ

          λ = 1.5 10⁻⁵ / 50

          λ = 3 10⁻⁷ m

    UV laser

3 0
3 years ago
Which of the following quantities is inversely proportional to the gravitational pull between two objects?
Contact [7]

Answer:

C

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

I hope this helps a little bit

7 0
3 years ago
Read 2 more answers
From the average distance of one of jupiter's moons to jupiter and its orbital period around jupiter, we can determine:
den301095 [7]

Answer: Jupiter's mass

Explanation:

From Kepler's third law:

T^2=\frac{4\pi^2}{GM}a^3

where T is the orbital period of a satellite, a is the average distance of the satellite from the Planet, M is the mass of the planet, G is the gravitational constant.

If the average distance of one of Jupiter's moons to Jupiter and its orbital period around Jupiter is given then mass of the Jupiter can be found:

\Rightarrow M_J=\frac{4\pi^2}{GT_m^2}a_m^3

4 0
3 years ago
Read 2 more answers
You're driving a vehicle of mass 1350 kg and you need to make a turn on a flat road. The radius of curvature of the turn is 71 m
sergey [27]

Answer:

v=12.65\ m.s^{-1}

Explanation:

Given:

  • mass of vehicle, m=1350\ kg
  • radius of curvature, r=71\ m
  • coefficient of friction, \mu=0.23

<u>During the turn to prevent the skidding of the vehicle its centripetal force must be equal to the opposite balancing frictional force:</u>

m.\frac{v^2}{r} =\mu.N

where:

\mu= coefficient of friction

N= normal reaction force due to weight of the car

v= velocity of the car

1350\times \frac{v^2}{71} =0.23\times (1350\times 9.8)

v=12.65\ m.s^{-1} is the maximum velocity at which the vehicle can turn without skidding.

5 0
3 years ago
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