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Stells [14]
3 years ago
9

As the frequency of a wave decreases the wavelength

Physics
1 answer:
alexandr402 [8]3 years ago
3 0
As frequency decreases , the wavelength will increase !!

frequency= speed of light ÷ wavelength

( inverse relationship )
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g A simple pendulum (consisting of a point mass suspended by a massless string) on the surface of the earth has a period of 1.00
leonid [27]

Answer:

Explanation:

The formula for time period of a pendulum is given as follows :

T = 2π\sqrt{\frac{l}{g} }

l is length of pendulum and g is acceleration due to gravity .

So time period of pendulum  is not dependent on the mass of the pendulum . If time period is same and length is also the same then acceleration due to gravity will also be the same . Hence the acceleration due to gravity at distant planet will be same as that on the earth.

5 0
3 years ago
Which of the following is a contact force?
Nutka1998 [239]
The contact force is indeed caused by "Contact". 

Air resistance is basically a type of friction, which is apparently present providing two object contact.

The rest selections are all interaction force, which is not necessarily caused by contact.
4 0
3 years ago
Read 2 more answers
คลื่นกลเกิดขึ้นได้อย่างไร
Feliz [49]

Mechanical waves are oscillation of matter, they are important because they all transfer energy from one place to another. There are 2 types of mechanical waves. A transverse wave where the particles vibrate perpendicular to the direction of energy travel and a longitudinal wave where particle vibrations are parallel to the direction of the energy transfer.


I hope it helps, Regards.

4 0
3 years ago
A man fires a silver bullet of mass 2g with a velocity of200m/sec into wall. What is the temperature changeof the bullet? Note:
Sphinxa [80]

F=nmv

where;

n=no. of bullets = 1

m=mass of bullets=2g *10^-3

V=velocity of bullets200m/sec

F=1

loss in Kinetic energy=gain in heat energy

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let M council M

=1/2V^2=S∆t

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K.E=MV^2/2

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2 councils 2

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K.E=40Js

H=mv∆t

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40Js=40/4.2=mc∆t

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=158.73°C

7 0
3 years ago
The primary reason a light bulb emits light is due to
Mashutka [201]
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</span>P=I^2 R
<span>where I is the current and R the resistance. The larger the resistance or the current in the resistor, the larger the power dissipated. Due to this dissipation of power, the temperature of the filament becomes very high, and the resistance becomes incandescent, emitting light.</span>
5 0
3 years ago
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