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4 years ago

Explain why atmospheric pressure decreases towards higher altitudes

Physics

1 answer:

denpristay [2]4 years ago

3 0

Answer:

At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels. ... Since most of the atmosphere's molecules are held close to the earth's surface by the force of gravity, air pressure decreases rapidly at first, then more slowly at higher levels.

Explanation:

happy to help:)

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A javelin thrower standing at rest holds the center of the javelin behind her head, then accelerates it through a distance of 70

JulijaS [17]

Answer:

a = 580 m/s^2

Explanation:

Given:

- Distance for accelerated throw s_a = 70 cm

- Angle of throw Q = 30 degrees

- Distance traveled by the javelin in horizontal direction x(f) = 75 m

- Initial height of throw y(0) = 0

- Final height of the javelin y(f) = -2 m

Find:

What was the acceleration of the javelin during the throw? Assume that it has a constant acceleration.

Solution:

- Compute initial components of the velocity:

V_x,i = V*cos(30)

V_y,i = V*sin(30)

- Use second equation of motion in horizontal direction:

x(f) = x(0) + V*cos(30)*t

75 = 0 + V*cos(30)*t

t = 75 /V*cos(30)

- Use equation of motion in vertical direction:

y(f) = y(0) + V_y,i*t + 0.5*g*t^2

Subs the values:

-2 = 0 + V*sin(30)*75/V*cos(30) - 4.905*(75/Vcos(30))^2

-2 = 75*tan(30) - 4.905*(5625/V^2*cos^2(30))

V^2 = 4.905*5625 / (2 + 75*tan(30))*cos^2(30)

V^2 = 812.0633

V = 28.5 m/s

- Use the third equation of motion in the interval of the throw:

V^2 = U^2 + 2*a*s_a

28.5^2 = 2*a*0.7

a = 580 m/s^2

6 0

3 years ago

A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begin

lyudmila [28]

Part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
$W= \int\limits^{0.540m}_{0} {F} \, dx = \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx =$
$=16000x+10000 \frac{x^2}{2} - 26000 \frac{x^3}{3}$
By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
$W=16000(0.540m)+10000 \frac{(0.540m)^2}{2} - 26000 \frac{(0.540m)^3}{3} =$
$=8733 J=8.73 kJ$

part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
$W=16000(0.95m)+10000 \frac{(0.95m)^2}{2} - 26000 \frac{(0.95m)^3}{3} =$
$=12280 J=12.28 kJ$

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3 years ago

Statie electricity refers to the transfer of _______

Nezavi [6.7K]

Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged. ... The rubbing of certain materials against one another can transfer negative charges, or electrons.

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3 years ago

Which statement explains the flow of heat? Heat moves from one place to another like a radiating wave. Heat moves as packets of

Kamila [148]

Answer:

C. Heat moves as molecules of one substance collide with molecules of another substance, transferring kinetic energy.

Explanation:

I tried it and got it right.

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3 years ago

A mercedes-benz 300sl (m 5 1700 kg) is parked on a road that rises 158 above the horizontal. what are the magnitudes of (a) the

vaieri [72.5K]

The normal force of a certain thing is the weight in force of the object multiplied by the sine function of the angle of inclination, be ∅ in this case. Given the mass of the car equal to 300 slug or 5.17 kg, then the nrmal force is 5.17*9.81 sin ∅ or 50.72 sin ∅. The frictional force is normal force times ∨k or coefficient of friction

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3 years ago