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garik1379 [7]
3 years ago
7

What must happen for liquid water to become water vapor?

Chemistry
2 answers:
Maurinko [17]3 years ago
5 0

C. The water molecules must gain kinetic energy.


Wittaler [7]3 years ago
5 0

Answer: Option (C) is the correct answer.

Explanation:

When liquid water is heated then molecules of water absorb heat and due to this vibration between water molecules increase to greater extent. As a result, kinetic energy of water molecules also increases.

Therefore, water starts to evaporate as the temperature reaches at 100 degree Celsius.

Thus, we can conclude that the water molecules must gain kinetic energy for liquid water to become water vapor.

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the symbol of an iron is Fe (ferous, feric).

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6 0
3 years ago
18. How many moles of atoms are there in each of
Lelechka [254]

a) 1 mole of Ne

b) i/2 mole of Mg

c) 1570 moles of Pb.

d) 2.18125*10^-13 moles of oxygen.

                     

Explanation:

The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.

6.23*10^23= 1/ 6.23*10^23

                   = 1 mole

The number of moles calculated by Avogadro's number in 3.01*10^23 of  Mg

3.2*10^23=1/6.23*10^23

                = 1/2 moles of Pb.

Number of moles in 3.25*10^5 gm of lead.

atomic weight of Pb=

n=weight/atomic weight

  = 3.25*10^5/ 207

  = 1570 moles of Pb.

Number of moles 4.50 x 10-12 g O

number of moles= 4.50*10^-12/16

                            =  2.18125*10^-13 moles of oxygen.

3 0
3 years ago
Balance the following redox equation and identify the element oxidized, the element reduced, the oxidizing agent, and the reduci
earnstyle [38]

The charge of Br changed from –1 to 0, therefore it is the element which is oxidized. Since it is oxidized then Br is also the reducing agent.

 

The charge of Mn changed from +4 to +2 therefore it is the element which is reduced. Since Mn is reduced, then MnO2 is the oxidizing agent.

 

The half –reactions are:

Br: 2Br --> Br2 + 2e-

Mn: MnO2 --> Mn2+

First balance oxygen by adding H2O:

MnO2 --> Mn2+ + 2H2O

Then balance hydrogen by adding H+ ions:

4H+ + MnO2 --> Mn2 + 2H2O

Then the appropriate electrons:

4e- + 4H+ + MnO2 --> Mn2 + 2H2O

 

Multiply the half-reaction of Br by 2 because the half-reaction of Mn has 4 electrons.

4Br --> 2Br2 + 4e-

 

Combine the two half reactions and cancel common factors:

4Br-  +  4H+  +  MnO2 --> 2Br2  +  Mn2  +  2H2O

6 0
3 years ago
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