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kipiarov [429]
3 years ago
14

What is the minimum time that a warm up should last

Physics
2 answers:
Vladimir [108]3 years ago
7 0
5 minutes is the minimum time
djyliett [7]3 years ago
7 0
At minimum, a warm up stretch or exercise should last about 5 minutes. this way your muscles are well prepared 
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11. A 3.8 kg object is lifted 12 meters. Approximately how much work is performed during the lifting?
Marianna [84]
I found the answer for you if u need any help ask anytime!

3 0
3 years ago
A waitperson carrying a tray with a platter on it tips the tray at an angle of 12 degrees below the horizontal. If the gravitati
Tasya [4]

Answer:1.04 N

Explanation:

Given

Gravitational Force on the Platter is 5 N

Tray makes an angle of \theta =12^{\circ}

This gravitational Force has components along and Perpendicular to Platter

Perpendicular Force W_p=W\cos \theta

W_p=5\times \cos 12=4.89 N

Along the Tray

W_{along}=W\sin \theta

W_{along}=5\times \sin 12=1.04 N

Thus 1.04 N is the magnitude of force that will cause Platter to slide down  

7 0
3 years ago
4. If the Kitty Hawk Flyer has 12 HP, do some research to find out how to express this power in the SI system and report the num
lesya [120]

Product of my research: 1 HP = 746 watts .

12 HP = (12 x 746 W) = 8,952 W

8,952 W = 8.952 kW
8 0
3 years ago
Read 2 more answers
I NEED HELP
Oduvanchick [21]

Answer:

the answer is different

Explanation:

i took the test

3 0
3 years ago
in order to qualify for the finals in a racing event, a race car must achieve an average speed of 278 km/h on a track with a tot
Pachacha [2.7K]

The minimum average speed it must have in the second half of the event in order to qualify is 414.7 km/h.

<h3>What is average speed?</h3>

The average speed of an object is the ratio of total distance traveled by the object to the total time of motion of the object.

<h3>Total time taken by the car during the entire race</h3>

time = distance/average speed

time = (1.41 km) / (278 km/h)

time = 0.0051 hr

The car travels the first half of the race, d (¹/₂ x 1410 m) at 210 km/h;

d = 705 m = 0.705 km

t1 = 0.705/210

t1 = 0.0034 hr

<h3>time for the second half</h3>

t2 = 0.0051 - 0.0034 hr

t2 = 0.0017 hr

<h3>minimum average speed of the second half</h3>

v = d/t

v = 0.705 km / 0.0017 hr

v = 414.7 km/hr

Thus, the minimum average speed it must have in the second half of the event in order to qualify is 414.7 km/h.

Learn more about average speed here: brainly.com/question/4931057

#SPJ1

6 0
1 year ago
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